单击TextView中的电话号码或电子邮件地址时出错

Question

我有工作链接的代码和TextView可以编辑。

以及应用程序中打开的链接。

与链接一起工作，但与(邮件地址，电话号码)不工作

我怎么才能解决这个问题？

单击电话号码或电子邮件地址：时出错：

“‘NSInvalidArgumentException”，原因：“指定的URL有一个不受支持的方案。只支持HTTP和HTTPS URL。”

import SafariServices

func textView(_ textView: UITextView, shouldInteractWith URL: URL, in characterRange: NSRange, interaction: UITextItemInteraction) -> Bool {
    // Open links with a SFSafariViewController instance and return false to prevent the system to open Safari app
    let safariViewController = SFSafariViewController(url: URL)
    present(safariViewController, animated: true, completion: nil)
    return false
}
override func viewWillDisappear(_ animated: Bool) {
    super.viewWillDisappear(animated)
    NotificationCenter.default.removeObserver(self)
}
@objc func viewTapped(_ aRecognizer: UITapGestureRecognizer) {
    self.view.endEditing(true)
}
// when you tap on your textView you set the property isEditable to true and you´ll be able to edit the text. If you click on a link you´ll browse to that link instead
@objc func textViewTapped(_ aRecognizer: UITapGestureRecognizer) {
    viewText.dataDetectorTypes = []
    viewText.isEditable = true
    viewText.becomeFirstResponder()
}
// this delegate method restes the isEditable property when your done editing
func textViewDidEndEditing(_ textView: UITextView) {
    viewText.isEditable = false
    //viewText.dataDetectorTypes = .all
    viewText.dataDetectorTypes = .link
}

Answer 1

您所看到的错误是因为您试图在Safari中打开电子邮件或电话号码，而它无法处理这类方案。

因此，我假设您希望打开您的Safari视图控制器的链接，并打开电子邮件和电话号码与其他东西。

首先更改为处理所有链接，然后执行如下操作：

func textView(_ textView: UITextView, shouldInteractWith URL: URL, in characterRange: NSRange, interaction: UITextItemInteraction) -> Bool {
    if (URL.scheme?.contains("mailto"))! {
        // Handle emails here
    } else if (URL.scheme?.contains("tel"))! {
        // Handle phone numbers here
    } else if (URL.scheme?.contains("http"))! || (URL.scheme?.contains("https"))! {
        // Handle links
        let safariViewController = SFSafariViewController(url: URL)
        present(safariViewController, animated: true, completion: nil)
    } else {
        // Handle anything else that has slipped through.
    }

    return false
}