Python jsonschema验证

Question

在Python中，我需要像这样验证复杂的json数据结构：

datainstances = {"apache1" :{"user":1,"dirname":"apache1dir","blah":42},"apache2" :{"user":"apache2","dirname":"apache2dir"},"apache3" :{"user1":"apache2","dirname":"apache2dir"}}

因此，我对这个模式使用jsonschema验证函数。

schemainstances = { 

                    "definitions" :{
                      "instance":{
                        "type":"object",
                        "properties": {
                          "user": {"type":"string"},
                          "dirname": {"type":"string"},
                          "blah": {"type":"string"}

                        },
                        "required" : ["user","blah"]
                      }
                  },
                  "type":"object",
                  "patternProperties": {
                    "^[a-z]+$": {"$ref": "#/definitions/instance"}  
                  }

}

我的目的是它不应该将这个json结构验证为：

1. apache1的用户属性必须是一个字符串
2. apache1的blah属性也必须是字符串。

我做错了吗？是我没看到的东西

编辑代码

import json
from jsonschema import validate
schemainstances = { 

                    "definitions" :{
                      "instance":{
                        "type":"object",
                        "properties":{
                          "user": {"type":"string"},
                          "dirname": {"type":"string"},
                          "blah": {"type":"string"}

                        },
                        "required" : ["user","blah"]
                      }
                  },
                  "type":"object",
                  "patternProperties":{
                    "^[a-z]+$": {"$ref": "#/definitions/instance"}  
                  }

}



datainstances = {"apache1" :{"user":1,"dirname":"apache1dir","blah":42},"apache2" :{"user":"apache2","dirname":"apache2dir"},"apache3" :{"user1":"apache2","dirname":"apache2dir"}}


retour = validate(datainstances,schemainstances)

print(retour)

Answer 1

您的patternProperties条目有regex“^a+$”。关键是"apache1“。此键与regex不匹配，因为它包含一个数字。因为patternProperties不匹配，所以对数据没有强制约束。一切都会证明。也许您需要"^a-z0-9+$“或”^a+0-9$“或”^a“。