我使用一个JSON对象从不同的网站获取新闻标题。当我解压缩它时,我可以访问一个标题,但是当我试图循环这些项目并将它们添加到列表中以获得所有标题时,我会得到以下错误:
“System.Collections.Generic.List.Add(String)”的最佳重载方法匹配有一些无效的参数
我正在使用newtonsoft.json,然后将它变成一个动态对象,以便通过点符号访问。
JSON示例
{
"status": "ok",
"totalResults": 10,
"articles": [{
"source": {
"id": "bloomberg",
"name": "Bloomberg"
},
"author": null,
"title": "Here’s Where the GOP Tax Plan Stands Right Now",
"description": "The House is scheduled to vote Tuesday on the tax bill and Senate leaders intend to bring the measure up as soon as they get it.",
"url": "http://www.bloomberg.com/news/articles/2017-12-19/house-plans-early-vote-democrats-plan-drama-tax-debate-update",
"urlToImage": "https://assets.bwbx.io/images/users/iqjWHBFdfxIU/isN9fqUqLwpE/v0/1200x800.jpg",
"publishedAt": "2017-12-19T09:00:00Z"
}, {
"source": {
"id": "bloomberg",
"name": "Bloomberg"
},
"author": "Dana Hull, Sarah Frier",
"title": "Elon Musk Appears to Have Misfired Direct Message to Oculus CTO",
"description": "Elon Musk appears to have just given his 16.7 million Twitter followers what he meant to send to the co-founder of the virtual-reality company Oculus: his phone number.",
"url": "http://www.bloomberg.com/news/articles/2017-12-19/elon-musk-appears-to-have-misfired-direct-message-to-oculus-cto",
"urlToImage": "https://assets.bwbx.io/images/users/iqjWHBFdfxIU/iqJHjveOq1j8/v1/1200x740.jpg",
"publishedAt": "2017-12-19T21:41:36Z"
}]
}代码:
// Set base Website
var url = "https://newsapi.org/v2/top-headlines?sources=";
// Initiate Client
System.Net.WebClient client = new System.Net.WebClient();
// Get JSON Data
var json = client.DownloadString(url + site + apiKey);
// Convert to dynamic object
dynamic jOutput = JsonConvert.DeserializeObject(json);
// Get Articles
var articles = jOutput.articles;
//Declare List
List<String> titles = new List<String>();
foreach (var article in articles)
{
var articleTitle = article.title;
titles.Add(articleTitle);
}
string title = jOutput.articles[0].title;
//string txt = items[0].title;发布于 2017-12-20 01:06:57
当反序列化为对象或动态类型时,Newtonsoft实际上将为您提供JValue项。
所以,这里的这一行:
var articleTitle = article.title;articleType是JValue型,而不是string型。因此,当您调用List<string>.Add(articleType) -它失败了,因为没有过载接受一个JValue。
幸运的是,JValue有重载的cast运算符,它允许您展开实际值。只需将上面的行更改为:
string articleTitle = article.title;足以让你的代码正常工作。
https://stackoverflow.com/questions/47897343
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