假设我们给出了一个API函数f(Stream s),将包含在流中的二进制数据放入数据库中。我想使用f将一个文件放入数据库,但我希望预先压缩数据。因此,我想我可以做以下几件事:
var fileStream= File.OpenRead(path);
using(var dstream = new DeflateStream(fileStream, CompressionLevel.Optimal))
f(dstream);但是,似乎DeflateStream只写入流fileStream,而在压缩时不从中读取。在我发现的所有示例中,流的CopyTo方法都用于压缩或解压缩。但是这意味着在将压缩数据的副本传递给f之前,我必须将其保存在内存中,例如:
var memoryStream = new MemoryStream();
using(var fileStream= File.OpenRead(path))
using(var dstream = new DeflateStream(memoryStream, CompressionLevel.Optimal)) {
fileStream.CopyTo(dstream);
memoryStream.Seek(0, SeekOrigin.Begin);
f(memoryStream);
} 有没有避免使用MemoryStream的方法?
为了一些评论员的持久性,我添加了一个完整的示例:更新:
using System;
using System.IO;
using System.IO.Compression;
public class ThisWouldBeTheDatabaseClient {
public void f(Stream s) {
// some implementation I don't have access to
// The only thing I know is that it reads data from the stream in some way.
var buffer = new byte[10];
s.Read(buffer,0,10);
}
}
public class Program {
public static void Main() {
var dummyDatabaseClient = new ThisWouldBeTheDatabaseClient();
var dataBuffer = new byte[1000];
var fileStream= new MemoryStream( dataBuffer ); // would be "File.OpenRead(path)" in real case
using(var dstream = new DeflateStream(fileStream, CompressionLevel.Optimal))
dummyDatabaseClient.f(dstream);
}
}f的虚拟实现中的读取操作抛出一个异常:不支持从压缩流中读取InvalidOperationException: read。在结束评论中的讨论后,我假设DeflateStream不可能实现所期望的行为,但是第三方库中有其他选择。
发布于 2017-12-14 12:29:57
为此您可以使用SharpCompress。它的DeflateStream允许您动态读取压缩数据,这正是您想要的。
以下是一个基于Rufo爵士的完整示例:
using System;
using System.IO;
using SharpCompress.Compressors;
using SharpCompress.Compressors.Deflate;
using System.Linq;
public class Program
{
public static void Main()
{
var dataBuffer = Enumerable.Range(1, 50000).Select(e => (byte)(e % 256)).ToArray();
using (var dataStream = new MemoryStream(dataBuffer))
{
// Note: this refers to SharpCompress.Compressors.Deflate.DeflateStream
using (var deflateStream = new DeflateStream(dataStream, CompressionMode.Compress))
{
ConsumeStream(deflateStream);
}
}
}
public static void ConsumeStream(Stream stream)
{
// Let's just prove we can reinflate to the original data...
byte[] data;
using (var decompressed = new MemoryStream())
{
using (var decompressor = new DeflateStream(stream, CompressionMode.Decompress))
{
decompressor.CopyTo(decompressed);
}
data = decompressed.ToArray();
}
Console.WriteLine("Reinflated size: " + data.Length);
int errors = 0;
for (int i = 0; i < data.Length; i++)
{
if (data[i] != (i + 1) % 256)
{
errors++;
}
}
Console.WriteLine("Total errors: " + errors);
}
}或者使用示例代码:
using System;
using System.IO;
using SharpCompress.Compressors;
using SharpCompress.Compressors.Deflate;
public class ThisWouldBeTheDatabaseClient {
public void f(Stream s) {
// some implementation I don't have access to
// The only thing I know is that it reads data from the stream in some way.
var buffer = new byte[10];
s.Read(buffer,0,10);
}
}
public class Program {
public static void Main() {
var dummyDatabaseClient = new ThisWouldBeTheDatabaseClient();
var dataBuffer = new byte[1000];
var fileStream= new MemoryStream( dataBuffer ); // would be "File.OpenRead(path)" in real case
using(var dstream = new DeflateStream(
fileStream, CompressionMode.Compress, CompressionLevel.BestCompression))
dummyDatabaseClient.f(dstream);
}
}这现在不抛出异常,并将服务于压缩数据。
发布于 2017-12-14 09:53:14
DeflateStream只是一个包装器,需要一个流来处理压缩的数据。所以你必须使用两个流。
有没有避免使用MemoryStream的方法?
是。
您需要一个流来存储临时数据,而不消耗(太多)内存。相反,使用MemoryStream,您可以使用一个临时文件。
对于懒惰的人(像我这样的第一位),让我们创建一个类,它的行为主要像一个MemoryStream
public class TempFileStream : FileStream
{
public TempFileStream() : base(
path: Path.GetTempFileName(),
mode: FileMode.Open,
access: FileAccess.ReadWrite,
share: FileShare.None,
bufferSize: 4096,
options: FileOptions.DeleteOnClose | FileOptions.Asynchronous | FileOptions.Encrypted | FileOptions.RandomAccess)
{
}
}这里的重要部分是FileOptions.DeleteOnClose,它将在您释放流时删除临时文件。
然后再用它
using (var compressedStream = new TempFileStream())
{
using (var deflateStream = new DeflateStream(
stream: compressedStream,
compressionLevel: CompressionLevel.Optimal,
leaveOpen: true))
using (var fileStream = File.OpenRead(path))
{
fileStream.CopyTo(deflateStream);
}
f(compressedStream);
}https://stackoverflow.com/questions/47809155
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