我对SQL不太感兴趣,我对试图更改查询有以下疑问(我使用MySql作为DB)。
所以我有一个疑问:
SELECT
MD.id AS market_id,
MD.market_name AS market_name,
CN.id AS commodity_details_id,
CD.commodity_name_en AS commodity_name_en,
CN.commodity_name AS commodity_name,
CD.image_link AS image_link,
CN.description AS description,
MD_CD.id AS price_serie_id,
MCPS.avg_price AS today_avg_price,
YMCPS.avg_price AS yesterday_avg_price,
CASE WHEN MCPS.market_commodity_details_id IS NOT NULL
THEN
MCPS.currency
ELSE
YMCPS.currency
END AS currency,
CASE WHEN MCPS.market_commodity_details_id IS NOT NULL
THEN
MCPS.measure_unit
ELSE
YMCPS.measure_unit
END AS measure_unit
FROM MarketDetails_CommodityDetails AS MD_CD
INNER JOIN MarketDetails AS MD
ON MD_CD.market_details_id = MD.id
INNER JOIN CommodityDetails as CD
ON MD_CD.commodity_details_id = CD.id
INNER JOIN CommodityName AS CN
ON CD.id=CN.commodity_details_id
LEFT JOIN
(
SELECT
Market_Commodity_Price_Series.id AS price_series_id,
market_commodity_details_id
, avg_price
, CU.ISO_4217_cod AS currency
, MU.unit_name AS measure_unit
FROM Market_Commodity_Price_Series
INNER JOIN MeasureUnit AS MU
ON Market_Commodity_Price_Series.measure_unit_id = MU.id
INNER JOIN Currency AS CU
ON Market_Commodity_Price_Series.currency_id = CU.id
WHERE price_date = CURDATE()
) AS MCPS
ON MD_CD.id = MCPS.market_commodity_details_id
LEFT JOIN
(
SELECT
Market_Commodity_Price_Series.id AS price_series_id,
market_commodity_details_id
, avg_price
, CU.ISO_4217_cod AS currency
, MU.unit_name AS measure_unit
FROM Market_Commodity_Price_Series
INNER JOIN MeasureUnit AS MU
ON Market_Commodity_Price_Series.measure_unit_id = MU.id
INNER JOIN Currency AS CU
ON Market_Commodity_Price_Series.currency_id = CU.id
WHERE price_date = ADDDATE(CURDATE(), -1)
) AS YMCPS
ON MD_CD.id = YMCPS.market_commodity_details_id
WHERE
MD_CD.commodity_details_id = 4
AND
MD.localization_id = 2这意味着返回两个这样的记录,这些记录代表了某个特定商品的销售市场,如下所示:
market_id market_name commodity_details_id commodity_name_en commodity_name image_link description price_serie_id today_avg_price yesterday_avg_price currency measure_unit
---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
4 Tambacounda Market N1 4 Red onion Red onion https://firebasestorage.googleapis.com/v0/b/blablabla.appspot.com/o/img%2Ficons%2Fagrimarket%2Fcommodity%2Fonion-red.png?alt=media&token=4ec9de4e-6e5a-4198-9bcd-21b692760618 Red onion 24 20,15 18,94 XOF kilogram
5 Tambacounda Market N2 4 Red onion Red onion https://firebasestorage.googleapis.com/v0/b/blablabla.appspot.com/o/img%2Ficons%2Fagrimarket%2Fcommodity%2Fonion-red.png?alt=media&token=4ec9de4e-6e5a-4198-9bcd-21b692760618 Red onion 28 13,7 16,2 XOF kilogram 好的,我想添加一个新的字段,表示这种商品可获取的市场数量(基本上是检索到的记录的数量),所以我尝试这样做:
SELECT
MD.id AS market_id,
MD.market_name AS market_name,
count(MD.id) AS market_total_number,
CN.id AS commodity_details_id,
CD.commodity_name_en AS commodity_name_en,
CN.commodity_name AS commodity_name,
CD.image_link AS image_link,
CN.description AS description,
MD_CD.id AS price_serie_id,
MCPS.avg_price AS today_avg_price,
YMCPS.avg_price AS yesterday_avg_price,
CASE WHEN MCPS.market_commodity_details_id IS NOT NULL
THEN
MCPS.currency
ELSE
YMCPS.currency
END AS currency,
CASE WHEN MCPS.market_commodity_details_id IS NOT NULL
THEN
MCPS.measure_unit
ELSE
YMCPS.measure_unit
END AS measure_unit
FROM MarketDetails_CommodityDetails AS MD_CD
INNER JOIN MarketDetails AS MD
ON MD_CD.market_details_id = MD.id
INNER JOIN CommodityDetails as CD
ON MD_CD.commodity_details_id = CD.id
INNER JOIN CommodityName AS CN
ON CD.id=CN.commodity_details_id
LEFT JOIN
(
SELECT
Market_Commodity_Price_Series.id AS price_series_id,
market_commodity_details_id
, avg_price
, CU.ISO_4217_cod AS currency
, MU.unit_name AS measure_unit
FROM Market_Commodity_Price_Series
INNER JOIN MeasureUnit AS MU
ON Market_Commodity_Price_Series.measure_unit_id = MU.id
INNER JOIN Currency AS CU
ON Market_Commodity_Price_Series.currency_id = CU.id
WHERE price_date = CURDATE()
) AS MCPS
ON MD_CD.id = MCPS.market_commodity_details_id
LEFT JOIN
(
SELECT
Market_Commodity_Price_Series.id AS price_series_id,
market_commodity_details_id
, avg_price
, CU.ISO_4217_cod AS currency
, MU.unit_name AS measure_unit
FROM Market_Commodity_Price_Series
INNER JOIN MeasureUnit AS MU
ON Market_Commodity_Price_Series.measure_unit_id = MU.id
INNER JOIN Currency AS CU
ON Market_Commodity_Price_Series.currency_id = CU.id
WHERE price_date = ADDDATE(CURDATE(), -1)
) AS YMCPS
ON MD_CD.id = YMCPS.market_commodity_details_id
WHERE
MD_CD.commodity_details_id = 4
AND
MD.localization_id = 2我只是将这个SELECT添加到检索字段列表中:
count(MD.id) AS market_total_number, 因为我的想法是对检索到的记录进行计数,但是现在执行我的查询将获得以下错误消息:
#42000In aggregated query without GROUP BY, expression #1 of SELECT list contains nonaggregated column 'digital_services_DB.MD.id'; this is incompatible with sql_mode=only_full_group_by为什么?怎么啦?我遗漏了什么?如何解决这个问题并取得预期的结果?
发布于 2017-12-06 10:18:49
当您想要创建一个包含诸如count之类的聚合函数的select并检索任何字段时,您必须使用group by。
你可以在:https://dev.mysql.com/doc/refman/5.7/en/group-by-functions.html中读到更多关于它的信息。
因此,如果在查询结束时添加这一项,它就会正常工作。
GROUP BY
MD.id
,MD.market_name
,CN.id
,CD.commodity_name_en
,CN.commodity_name
,CD.image_link
,CN.description
,MD_CD.id
,MCPS.avg_price
,YMCPS.avg_price发布于 2017-12-06 10:17:59
当使用聚合函数时,组by是强制性的。尝尝这个
SELECT count(market_id) AS market_total_number,
market_id,
market_name,
market_total_number,
commodity_details_id,
commodity_name_en,
commodity_name,
image_link,
description,
price_serie_id,
today_avg_price,
yesterday_avg_price,
currency ,
measure_units
FROM (
SELECT
MD.id AS market_id,
MD.market_name AS market_name,
count(MD.id) AS market_total_number,
CN.id AS commodity_details_id,
CD.commodity_name_en AS commodity_name_en,
CN.commodity_name AS commodity_name,
CD.image_link AS image_link,
CN.description AS description,
MD_CD.id AS price_serie_id,
MCPS.avg_price AS today_avg_price,
YMCPS.avg_price AS yesterday_avg_price,
CASE WHEN MCPS.market_commodity_details_id IS NOT NULL
THEN
MCPS.currency
ELSE
YMCPS.currency
END AS currency,
CASE WHEN MCPS.market_commodity_details_id IS NOT NULL
THEN
MCPS.measure_unit
ELSE
YMCPS.measure_unit
END AS measure_unit
FROM MarketDetails_CommodityDetails AS MD_CD
INNER JOIN MarketDetails AS MD
ON MD_CD.market_details_id = MD.id
INNER JOIN CommodityDetails as CD
ON MD_CD.commodity_details_id = CD.id
INNER JOIN CommodityName AS CN
ON CD.id=CN.commodity_details_id
LEFT JOIN
(
SELECT
Market_Commodity_Price_Series.id AS price_series_id,
market_commodity_details_id
, avg_price
, CU.ISO_4217_cod AS currency
, MU.unit_name AS measure_unit
FROM Market_Commodity_Price_Series
INNER JOIN MeasureUnit AS MU
ON Market_Commodity_Price_Series.measure_unit_id = MU.id
INNER JOIN Currency AS CU
ON Market_Commodity_Price_Series.currency_id = CU.id
WHERE price_date = CURDATE()
) AS MCPS
ON MD_CD.id = MCPS.market_commodity_details_id
LEFT JOIN
(
SELECT
Market_Commodity_Price_Series.id AS price_series_id,
market_commodity_details_id
, avg_price
, CU.ISO_4217_cod AS currency
, MU.unit_name AS measure_unit
FROM Market_Commodity_Price_Series
INNER JOIN MeasureUnit AS MU
ON Market_Commodity_Price_Series.measure_unit_id = MU.id
INNER JOIN Currency AS CU
ON Market_Commodity_Price_Series.currency_id = CU.id
WHERE price_date = ADDDATE(CURDATE(), -1)
) AS YMCPS
ON MD_CD.id = YMCPS.market_commodity_details_id
WHERE
MD_CD.commodity_details_id = 4
AND
MD.localization_id = 2
) base
group by market_id,
market_name,
market_total_number,
commodity_details_id,
commodity_name_en,
commodity_name,
image_link,
description,
price_serie_id,
today_avg_price,
yesterday_avg_price,
currency ,
measure_unitshttps://stackoverflow.com/questions/47671586
复制相似问题