在管道中将参数从文件传递到shell

Question

基本上，我试图从文件中将属性传递给shell。

我有一个文件"docker_info“，它的工作空间中有以下内容

IMAGE_NAME='Docker-image'

IMAGE_VERIONS='Docker-1.3.5'

下面是我的管道脚本：

node
{

load "${WORKSPACE}/docker_info"

sh " echo ${IMAGE_NAME}" // here getting expected output: Docker-image

stage('Executing SHELL SCRIPING TO CHECK DOCKER IMAGE')

        sh '''

         echo "$DOCKER_IMAGE"

            if [ -z "${IMAGE_NAME}" ]     //(also tried "$IMAGE_NAME")
            then
            echo "Docker image not found."
            exit 0
            fi

             echo "${IMAGE_NAME}:started pushing image"

         '''   
}

输出：

[Test_BUILD_PIPELINE] Running shell script

+ echo Docker-image

Docker-image     

**Entering stage Executing SHELL SCRIPTING TO CHECK DOCKER IMAGE**

Proceeding

[Pipeline] sh

[Test_BUILD_PIPELINE] Running shell script

+  echo ''
+ '[' -z '' ']'

+ echo 'Docker image not found. Skip pushing Docker image'

Docker image not found. Skip pushing Docker image

+ exit 0

请注意，进入阶段后，我将不会看到期望值(Docker-image)，而是显示: echo‘’。

我试过几种方法，但都没有用。

Answer 1

试一试

    sh """

     echo '$DOCKER_IMAGE'

        if [ -z '$IMAGE_NAME' ]  
        then
        echo 'Docker image not found.'
        exit 0
        fi

         echo '$IMAGE_NAME:started pushing image' 

     """

Answer 2

什‘’

。/path/to/the/docker_info

如果-z "$IMAGE_NAME“

然后

回声“找不到码头形象”

出口0

fi

回波"$IMAGE_NAME:started推送图像“

“”“