用Xcode编译SoundTouch？

Question

我正试图在我的Xcode项目中编译SoundTouch框架，但老实说，我不知道我在做什么。

有人有什么指示吗？

我到目前为止做了什么，

运行./bootstrap将给出以下输出

autoreconf: Entering directory `.'
autoreconf: configure.ac: not using Gettext
autoreconf: running: aclocal -I config/m4 --output=aclocal.m4t
Can't exec "aclocal": No such file or directory at /usr/local/Cellar/autoconf/2.69/share/autoconf/Autom4te/FileUtils.pm line 326.
autoreconf: failed to run aclocal: No such file or directory

如果我没记错的话，Mac没有autoreconf，对吗？

SoundTouch显然至少需要GCC 4.4，但Mac只有GCC 4.3，所以我从homebrew下载了GCC 7，但是只与命令gcc-7 ./bootstrap一起使用它给出了以下输出

gcc-7 bootstrap
ld: warning: ignoring file bootstrap, file was built for unsupported file format ( 0x23 0x20 0x24 0x49 0x64 0x3A 0x20 0x62 0x6F 0x6F 0x74 0x73 0x74 0x72 0x61 0x70 ) which is not the architecture being linked (x86_64): bootstrap
Undefined symbols for architecture x86_64:
  "_main", referenced from:
     implicit entry/start for main executable
ld: symbol(s) not found for architecture x86_64
collect2: error: ld returned 1 exit status

如何成功编译SoundTouch？

编辑：

我尝试将基本文件复制到一个文件夹中，将其添加到我的项目中并进行编译。

现在我得到了这个错误：

Undefined symbols for architecture x86_64:
  "soundtouch::SoundTouch::SoundTouch()", referenced from:
      MyAudioProcessor::MyAudioProcessor() in libMy.a(PluginProcessor.o)
ld: symbol(s) not found for architecture x86_64
clang: error: linker command failed with exit code 1 (use -v to see invocation)

为什么要说有未定义的符号？

Answer 1

我将SoundTouch的基本文件复制到项目的“编译源代码”定义中。

现在它编译了。

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