我正在编写一个函数来解析一个.csv文件,并且我在valgrind中得到了一个错误。具体来说,就是这样:
==5450== Invalid write of size 8
==5450== at 0x404FA0: parse_exemplars (util.c:568)
==5450== by 0x40508E: get_test_and_train_data (util.c:595)
==5450== by 0x402737: setup (pony_gp.c:727)
==5450== by 0x4027E5: main (pony_gp.c:761)这是带有指示错误行的代码:
csv_reader *reader = init_csv(file_name, ',');
double **fitness_cases, *targets;
int num_columns = 122;
int num_lines = 121;
// leave space for NULL at end
fitness_cases = malloc(sizeof(double **) * num_lines);
for (int i = 0; i < num_lines; i++) {
fitness_cases[i] = malloc(sizeof(double *));
for (int k = 0; k < num_columns; k++) {
fitness_cases[i] = malloc(sizeof(double) * (num_columns - 1));
}
}
// leave space for NAN at end
targets = malloc(sizeof(double) * (num_lines));
csv_line *row;
int f_i = 0;
int t_i = 0;
while ((row = readline(reader))) {
int i;
for (i = 0; i < num_columns; i++) {
if (i == num_columns - 1) {
targets[t_i++] = atof(row->content[i]);
}
else {
fitness_cases[f_i][i] = atof(row->content[i]);
}
}
fitness_cases[f_i][i-1] = (double)NAN; //<----- This is where it says the error is, line 568.
f_i++;
}每当我检查fitness_casesf_i的大小时,我总是得到与(double)NAN大小相同的值,所以我猜想它在函数中出现得更早吗?
指向github页面的链接是(我询问的这个函数目前还没有在回购程序中更新):c
发布于 2017-11-28 03:04:07
fitness_cases[f_i][i-1] = (double)NAN; 这里的i-1值将是num_columns -1,但由于您已经将空间分配为
fitness_cases[i] = malloc(sizeof(double) * (num_columns - 1));第二个数组下标的最大索引可能会少一个ie num_columns - 2,否则就会超出界限。
例如:
fitness_cases[i] = 3 * sizeof(double);fitness_cases[i][0],fitness_cases[i][1],fitness_cases[i][2]都是有效的,fitness_cases[i][3]是不允许的,它将导致无效的写入,正如val差所指出的那样。
https://stackoverflow.com/questions/47523250
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