使用熊猫组来查找每组中文本的平均长度。

Question

我在用莎士比亚的语料库。

    act literature_type scene   scene_text  scene_title speaker title
0   1   Comedy  1   In delivering my son from me, I bury a second ...   Rousillon. The COUNT's palace.  COUNTESS    All's Well That Ends Well
1   1   Comedy  1   And I in going, madam, weep o'er my father's d...   Rousillon. The COUNT's palace.  BERTRAM All's Well That Ends Well
2   1   Comedy  1   You shall find of the king a husband, madam; y...   Rousillon. The COUNT's palace.  LAFEU   All's Well That Ends Well
3   1   Comedy  1   What hope is there of his majesty's amendment?  Rousillon. The COUNT's palace.  COUNTESS    All's Well That Ends Well
4   1   Comedy  1   He hath abandoned his physicians, madam; under...   Rousillon. The COUNT's palace.  LAFEU   All's Well That Ends Well

我想找到每个标题的平均scene_text长度。

我想用一些类似于：

all_works_by_speaker_df.groupby('title').apply(lambda x: np.mean(len(x)))

这只会返回每个标题中的场景数。

Answer 1

如果需要字符的len：

df = (all_works_by_speaker_df.groupby('title')['scene_text']
                            .apply(lambda x: np.mean(x.str.len()))
                            .reset_index(name='mean_len_text'))
print (df)

                       title  mean_len_text
0  All's Well That Ends Well           48.4

如果需要的话，使用len的单词，使用Vaishali's solution。

Answer 2

从列中取字符串的长度，然后由一个数组组成，这是您的播放标题，然后应用平均值。

mean_len = df.scene_text.str.len().groupby(df.title).mean()

Answer 3

分裂，卑劣

df.groupby('title').scene_text.apply(lambda x: x.str.split().str.len().mean())


title
All's Well That Ends Well    9.2