OWLAPI本体中的SWRL规则创建

Question

为了实验SWRL语言，我运行了以下简单的java代码(在Neatbeans 8.2中)：

String base = "http://www.prova/testont.owl";
IRI ontologyIRI = IRI.create(base);
OWLOntologyManager manager = OWLManager.createOWLOntologyManager();
OWLOntology ontology = manager.createOntology(ontologyIRI);
OWLDataFactory factory = manager.getOWLDataFactory();

OWLClass adult = factory.getOWLClass(IRI.create(ontologyIRI + "#Adult"));
OWLClass person = factory.getOWLClass(IRI.create(ontologyIRI + "#Person"));
OWLDataProperty hasAge = factory.getOWLDataProperty(IRI.create(ontologyIRI + "#hasAge"));

OWLNamedIndividual john = factory.getOWLNamedIndividual(IRI.create(ontologyIRI + "#John"));
OWLNamedIndividual andrea = factory.getOWLNamedIndividual(IRI.create(ontologyIRI + "#Andrea"));

OWLClassAssertionAxiom classAssertion = factory.getOWLClassAssertionAxiom(person, john);
manager.addAxiom(ontology, classAssertion);
classAssertion = factory.getOWLClassAssertionAxiom(person, andrea);
manager.addAxiom(ontology, classAssertion);

OWLDatatype integerDatatype = factory.getOWLDatatype(OWL2Datatype.XSD_INTEGER.getIRI());
OWLLiteral literal = factory.getOWLLiteral("41", integerDatatype);
OWLAxiom ax = factory.getOWLDataPropertyAssertionAxiom(hasAge, andrea, literal);
manager.addAxiom(ontology, ax);

literal = factory.getOWLLiteral("15", integerDatatype);
ax = factory.getOWLDataPropertyAssertionAxiom(hasAge, john, literal);
manager.addAxiom(ontology, ax);

SWRLRuleEngine ruleEngine = SWRLAPIFactory.createSWRLRuleEngine(ontology);
ruleEngine.createSWRLRule("r1", "Person(?p)^hasAge(?p,?age)^swrlb:greaterThan(?age,17) -> Adult(?p)");

manager.saveOntology(ontology, IRI.create(((new File("FILE_PATH")).toURI())));

我在下面的依赖项中使用maven：

 <dependency>
     <groupId>edu.stanford.swrl</groupId>
     <artifactId>swrlapi-drools-engine</artifactId>
     <version>1.1.4</version>
  </dependency>

我得到了以下错误：

线程"main“中的异常:无效的SWRL谓词'Person‘at org.swrlapi.parser.SWRLParser.generateEndOfRuleException(SWRLParser.java:479) at org.swrlapi.parser.SWRLParser.parseSWRLAtom(SWRLParser.java:210) at org.swrlapi.parser.SWRLParser.parseSWRLRule(SWRLParser.java:106) at org.swrlapi.factory.DefaultSWRLAPIOWLOntology.createSWRLRule(DefaultSWRLAPIOWLOntology.java:219) at org.swrlapi.factory.DefaultSWRLAPIOWLOntology.createSWRLRule(DefaultSWRLAPIOWLOntology.java:213) at org.swrlapi.factory.DefaultSWRLRuleAndQueryEngine.createSWRLRule(DefaultSWRLRuleAndQueryEngine.java:249) at ilc.cnr.it.swrl4morphology.SimpleToSWRL.main(SimpleToSWRL.java:450)

但是，如果我将本体保存在文件中，然后重新加载它，我就不会再得到错误了。似乎默认前缀是在第一次保存期间添加的。我觉得很奇怪..。

拜托，你能帮我理解一下我的错吗？

事先谢谢你，安德里亚

Answer 1

在保存和解析时，使用本体IRI作为基础，将相对IRIs (如“Person”)转换为绝对IRIs。