我试图使用以下数据集建立一个堆叠和分组的桶形图:
dfplot <- data.frame(organisms=c("M.musculus","D.melanogaster" ,"H.sapiens","O.sativa","S.pombe","C.familiaris",
"G.gallus","P.falciparum","A.thaliana","C.elegans","D.rerio","B.taurus","S.cerevisiae","R.norvegicus","C.intestinalis","B.subtilis","E.coli"),
KEGGv2=c(20,7,21,126,106,62,26,80,5,5,13,306,8,35,32,104,107),
KEGGv1=c(286,124,289,0,0,244,135,0,121,124,148,0,101,271,87,0,0),
Reactome=c(358,146,596,115,54,306,370,23,155,112,365,341,52,364,0,0,0))
# Melt the dataframe
melted <- melt(dfplot, "organisms")
# Reformat the data labels
melted$cat <- ''
melted[melted$variable == 'Reactome',]$cat <- "Reactome"
melted[melted$variable != 'Reactome',]$cat <- "KEGG"
ggplot(melted, aes(x=cat, y=value, fill=variable)) +
geom_bar(stat = 'identity', position = 'stack') +
facet_grid(~ organisms)+
scale_fill_manual(values=c("deepskyblue4", "lightblue1", "olivedrab2")) +
labs(y = "Number of Pathways") +
theme(axis.title.x=element_blank(),
axis.text.x=element_blank(),
axis.ticks.x=element_blank(),
legend.title=element_blank(),
strip.text.x = element_blank(),
strip.background = element_blank(),
panel.grid.major = element_blank(),
panel.grid.minor = element_blank(),
panel.background = element_blank(),
axis.line = element_line(colour = "black"))我的输出如下:

我在每个有机体中使用一个facet_grid,因为我希望在stack ( KEGGv1和KEGGv2)之间混合,然后与其他组Reactome进行分组。然而,在进行熔融时,x轴每个facet_grid将有两个标签(KEGG和Reactome,这是从熔融猫获得的变量)。我不想要那个标签所以我把它们去掉了。
我要做的是让每个组都有一个有机体的名字,这样17个分组栏中的每一个都会有相应的有机体的名称**。因此,我错过了,我尝试过几种方法,但我找不到合适的方法。
提前谢谢你,
发布于 2017-11-21 14:34:54
你可以做两件事来完成这个任务:
switch = 'x'参数在facet_grid中绘制图形下面的facet标签。以下是完整的示例:
ggplot(melted, aes(x=cat, y=value, fill=variable)) +
geom_bar(stat = 'identity', position = 'stack') +
facet_grid(~organisms, switch = 'x')+
scale_fill_manual(values=c("deepskyblue4", "lightblue1", "olivedrab2")) +
labs(y = "Number of Pathways") +
theme(axis.title.x=element_blank(),
axis.text.x=element_blank(),
axis.ticks.x=element_blank(),
legend.title=element_blank(),
panel.grid.major = element_blank(),
panel.grid.minor = element_blank(),
panel.background = element_blank(),
axis.line.y = element_line(colour = "black"),
strip.text = element_text(angle = 90))

我留下了默认的阴影背景,但您可以轻松地样式,您喜欢。
阿普罗二
你可能想考虑旋转这个情节。这要求您在调用facet之前使用coord_flip 翻转绘图的坐标。当我们转向另一个方向时,我们将facet参数更改为facet_grid(organisms~.)。引用x或y的所有其他参数都被替换:
ggplot(melted, aes(x=cat, y=value, fill=variable)) +
geom_bar(stat = 'identity', position = 'stack') +
coord_flip() +
facet_grid(organisms~., switch = 'y') +
scale_fill_manual(values=c("deepskyblue4", "lightblue1", "olivedrab2")) +
labs(y = "Number of Pathways") +
theme(axis.title.y=element_blank(),
axis.text.y=element_blank(),
axis.ticks.y=element_blank(),
legend.title=element_blank(),
panel.grid.major = element_blank(),
panel.grid.minor = element_blank(),
panel.background = element_blank(),
axis.line.x = element_line(colour = "black"),
strip.text.y = element_text(angle = 180))

发布于 2017-11-21 14:43:46
首先,你可以把生物标签设置在条子下面,而不是上面。这是通过将参数的facet_grid函数设置为"x“来建立的(参见下面的代码)。其次,您应该在主题函数调用中删除axis.title.x=element_blank()参数。更新后的代码如下。希望这能有所帮助!
ggplot(melted, aes(x = cat, y = value, fill =variable)) +
geom_bar(stat = 'identity', position = 'stack') +facet_grid(~organisms, switch="x")+
scale_fill_manual(values=c("deepskyblue4","lightblue1","olivedrab2"))+
ylab("Number of pathways")+
theme(axis.title.x=element_blank(),axis.text.x=element_blank(),axis.ticks.x=element_blank())+theme(legend.title=element_blank())+
theme(strip.background = element_blank())+theme(panel.grid.major = element_blank(), panel.grid.minor = element_blank(),panel.background = element_blank(), axis.line = element_line(colour = "black"))https://stackoverflow.com/questions/47415024
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