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社区首页 >问答首页 >在R数据帧的每一列中,用逗号",“来计数单词数

在R数据帧的每一列中,用逗号",“来计数单词数
EN

Stack Overflow用户
提问于 2017-11-19 17:33:38
回答 2查看 1.1K关注 0票数 2

我从人类蛋白质图谱下载了一个数据集,其中包含12,004种蛋白质的亚细胞定位注释。这个文件,我有子集,只包括“基因名称”,然后4列是如何可靠的位置(基于免疫荧光染色的细胞)。这些是"Validated">"Supported">"Approved">"Uncertain".

我想出了一个评分系统,我想应用于LC光谱计数数据集,我有1)权衡注释的质量,2)惩罚在拟议评分系统的图像中发现蛋白质的位置。

TLDR是指我需要计算以下数据集的每一列中有多少项,并获得该信息的数据。

代码语言:javascript
复制
df <- read.csv("proteinAtlas.csv")
dput(df)
structure(list(Gene_symbol = structure(1:49, .Label = c("AAAS", 
"AAMP", "AAR2", "AARD", "AARS", "AARS2", "AARSD1", "ABCA13", 
"ABCB6", "ABCB7", "ABCB8", "ABCC1", "ABCC4", "ABCD3", "ABCE1", 
"ABCF1", "ABCF2", "ABCF3", "ABHD10", "ABHD14B", "ABHD6", "ABI1", 
"ABI2", "ABL2", "ACAA1", "ACAA2", "ACACA", "ACAD9", "ACADM", 
"ACADS", "ACADVL", "ACAP1", "ACAP2", "ACAT1", "ACAT2", "ACBD3", 
"ACBD5", "ACIN1", "ACLY", "ACO2", "ACOT1", "ACOT13", "ACOT2", 
"ACOT7", "ACOT8", "ACOT9", "ACOX1", "ACP1", "ACP5"), class = "factor"), 
    Validated = structure(c(1L, 2L, 1L, 1L, 2L, 4L, 1L, 1L, 3L, 
    1L, 1L, 1L, 1L, 5L, 2L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
    5L, 1L, 1L, 4L, 4L, 1L, 1L, 1L, 1L, 4L, 1L, 1L, 5L, 1L, 1L, 
    1L, 1L, 1L, 1L, 1L, 1L, 1L, 6L, 1L, 1L), .Label = c("", "Cytosol", 
    "Golgi apparatus", "Mitochondria", "Peroxisomes", "Vesicles"
    ), class = "factor"), Supported = structure(c(1L, 9L, 1L, 
    1L, 1L, 1L, 1L, 1L, 5L, 10L, 10L, 12L, 1L, 1L, 1L, 1L, 4L, 
    1L, 1L, 6L, 1L, 3L, 1L, 11L, 1L, 10L, 2L, 1L, 1L, 10L, 10L, 
    1L, 1L, 1L, 4L, 8L, 1L, 11L, 7L, 10L, 1L, 1L, 1L, 4L, 13L, 
    1L, 1L, 1L, 1L), .Label = c("", "Actin filaments;Cytosol", 
    "Cell Junctions;Plasma membrane", "Cytosol", "Cytosol;Mitochondria;Nucleoplasm;Plasma membrane", 
    "Cytosol;Nucleoli;Nucleus", "Cytosol;Nucleoplasm;Plasma membrane", 
    "Golgi apparatus", "Microtubules", "Mitochondria", "Nucleoplasm", 
    "Plasma membrane", "Vesicles"), class = "factor"), Approved = structure(c(3L, 
    1L, 5L, 12L, 1L, 1L, 6L, 4L, 1L, 1L, 17L, 1L, 8L, 1L, 1L, 
    1L, 1L, 7L, 13L, 1L, 16L, 1L, 15L, 1L, 1L, 1L, 14L, 1L, 1L, 
    15L, 17L, 18L, 11L, 1L, 17L, 1L, 1L, 1L, 1L, 1L, 13L, 2L, 
    13L, 15L, 13L, 9L, 17L, 10L, 5L), .Label = c("", "Cell Junctions", 
    "Centrosome;Cytosol;Nuclear membrane", "Centrosome;Cytosol;Vesicles", 
    "Cytosol", "Cytosol;Nuclear membrane", "Cytosol;Nucleoli", 
    "Cytosol;Nucleoli;Plasma membrane", "Cytosol;Nucleoplasm;Plasma membrane", 
    "Cytosol;Nucleus", "Endosomes", "Lipid droplets", "Mitochondria", 
    "Nucleoli fibrillar center", "Nucleoplasm", "Nucleoplasm;Vesicles", 
    "Nucleus", "Vesicles"), class = "factor"), Uncertain = structure(c(1L, 
    1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
    1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 3L, 
    1L, 1L, 1L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
    1L, 1L, 1L), .Label = c("", "Cytosol;Plasma membrane", "Nucleoli"
    ), class = "factor")), .Names = c("Gene_symbol", "Validated", 
"Supported", "Approved", "Uncertain"), class = "data.frame", row.names = c(NA, 
-49L))

因此理想的输出应该类似于这个,或者,如果您愿意的话,dput():

代码语言:javascript
复制
structure(list(Gene_symbol = structure(1:29, .Label = c("AAAS", 
"AAMP", "AAR2", "AARD", "AARS", "AARS2", "AARSD1", "ABCA13", 
"ABCB6", "ABCB7", "ABCB8", "ABCC1", "ABCC4", "ABCD3", "ABCE1", 
"ABCF1", "ABCF2", "ABCF3", "ABHD10", "ABHD14B", "ABHD6", "ABI1", 
"ABI2", "ABL2", "ACAA1", "ACAA2", "ACACA", "ACAD9", "ACADM"), class = "factor"), 
    Validated = c(NA, 1L, NA, NA, 1L, 1L, NA, NA, 1L, NA, NA, 
    NA, NA, 1L, 1L, 1L, NA, NA, NA, NA, NA, NA, NA, NA, 1L, NA, 
    NA, 1L, 1L), Supported = c(NA, 1L, NA, NA, NA, NA, NA, NA, 
    4L, 1L, 1L, 1L, NA, NA, NA, NA, 1L, NA, NA, 3L, NA, 2L, NA, 
    1L, NA, 1L, 2L, NA, NA), Approved = c(3L, NA, 1L, 1L, NA, 
    NA, 2L, 3L, NA, NA, 1L, NA, 3L, NA, NA, NA, NA, 2L, 1L, NA, 
    2L, NA, 1L, NA, NA, NA, 1L, NA, NA), Uncertain = c(NA, NA, 
    NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, 
    NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA)), .Names = c("Gene_symbol", 
"Validated", "Supported", "Approved", "Uncertain"), class = "data.frame", row.names = c(NA, 
-29L))

在每一列中,大部分是由";“分隔的字符串;然而,在某些情况下,它们是像”原子核纤维中心“或”脂滴“这样的术语,它们由空格隔开,应该算作一个单词/术语。

我发现了计算R中字符串中的单词数的例子,其中:

代码语言:javascript
复制
d <- "foo,bar,fun"
length(strsplit(d,",")[[1]]
class(d)

但这只适用于“字符”类,而不适用于"data.frame“。

有人能建议如何在R中这样做吗?非常感谢!

EN

回答 2

Stack Overflow用户

回答已采纳

发布于 2017-11-19 17:37:18

我们可以使用str_count。循环除第一个列(lapply(df[-1], ..)以外的列,获取;添加1的计数,检查是否存在空字符串,并使用NA替换这些元素。

代码语言:javascript
复制
library(stringr)
df[-1] <- lapply(df[-1], function(x) (str_count(x, ";") + 1) * NA^(as.character(x) == ""))
票数 1
EN

Stack Overflow用户

发布于 2017-11-19 17:48:25

一种使用base的解决方案

代码语言:javascript
复制
result_df <- data.frame(t(apply(df,1,function(x){
    c(x[1],sapply(strsplit(as.character(x[-1]),";"),length))
})), stringsAsFactors = F)
names(result_df) <- c("Gene_symbol", "Validated", "Supported", "Approved", "Uncertain")
票数 0
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/47379863

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