使用漂亮汤python抓取具有相同类名的特定元素的麻烦

Question

我如何提取文本与状态信息半家具，立即提供家庭，半家具。

由于div class="proDetailsRowElm“有详细信息和状态信息，我最终会在列表中获得详细的状态信息。

你能帮我只得到状态信息吗？

HTML代码

<div class="proDetailsRowElm">
<label>Details:</label>
<div class="proDetailsRow__list">
<span class="proDetailsRow__item">3 Bathroom</span>
<span class="proDetailsRow__item">3 Balcony</span>
</div>
&nbsp;&nbsp;<a class='stop-propagation underline font-type-4 view-details-link' href="javascript:void(0);" onclick="stopPage=true;window.open('/propertyDetails/3-BHK-1800-Sq-ft-Multistorey-Apartment-FOR-Rent-Kadubeesanahalli-in-Bangalore&id=4d423330363332363633', '_blank');callDetailPropertData('30632663');addViewedPropertyToCookie('30632663',1);detailViewTrack('30632663');clicktrack('1', 'propertyId=30632663,'+'2', 'div'+',sessionId='+sessionId  ,'Rent','Kadubeesanahalli','Agent','91','Bangalore' ,'','', 'N','35,000','','3','Multistorey Apartment','','','8','','',false,'','',''); trackPropertyPosition('1', '2', '30632663', 'div')"></a>
</div>
<div class="proDetailsRowElm">
<label>Status:</label>
Semi-Furnished,
Available immediately for Family
</div>

​

Python代码

​

property_status_list=soup.find_all('div',class_='proDetailsRowElm')
for property_status in property_status_list:
    for element in property_status_list:
        print(element.text)

​

上面的代码输出

详情:3个浴室，3个阳台

状况:备有家具，可立即提供给家庭

所需输出

状况:备有家具，可立即提供给家庭

Answer 1

我不是BeautifulSoup专家，但你也许能用next_sibling

property_status_list=soup.find_all('div',class_='proDetailsRowElm')
for property_status in property_status_list:
    try:
        k = property_status.find('label', text='Status:').next_sibling
        print(repr(k))
    except:
        pass

返回：

'\nSemi-Furnished,\nAvailable immediately for Family\n'