我有一个抽象的类,我想测试。这个类中有一个用于我的DAO的抽象属性,我在继承的类中定义了这个属性。
public abstract class DeviceGroupManagerBase<TDeviceGroup> where TDeviceGroup : DeviceGroup
{
protected abstract IDeviceGroupDao<TDeviceGroup> DeviceGroupDao { get; }
public TDeviceGroup UpdateDeviceIndexes(Device device)
{
return DeviceGroupDao.GetDeviceGroup(device.Group.Id);
}
}我想测试Updatedeviceindexes方法,所以我尝试模拟一个名为DeviceGroupDao的属性。
[TestFixture]
[Category("Unit")]
public class DeviceGroupManagerBaseTests
{
private IFixture fixture;
private Mock<DeviceGroupManagerBase<DeviceGroup>> subject;
private Mock<IDeviceGroupDao<DeviceGroup>> deviceGroupDaoMock;
private DeviceGroupManagerBase<DeviceGroup> Manager => subject.Object;
[TestFixtureSetUp]
public void Init()
{
fixture = new Fixture().Customize(new AutoMoqCustomization());
deviceGroupDaoMock = fixture.Freeze<Mock<IDeviceGroupDao<DeviceGroup>>>();
subject = fixture.Freeze<Mock<DeviceGroupManagerBase<DeviceGroup>>>();
}
[Test]
public void TestUpdateDeviceIndexes()
{
var device = fixture.Create<Device>();
var deviceGroup = fixture.Create<DeviceGroup>();
deviceGroupDaoMock.Setup(x => x.GetDeviceGroup(It.IsAny<int>())).Returns(deviceGroup);
var result = Manager.UpdateDeviceIndexes(device);
// The resultDeviceGroup will not be contain a previously defined object
Assert.AreEqual(deviceGroup.Id, result.Id);
}
}我还试图以这种方式为我的设备对象添加注册:
fixture.Register(() => deviceGroup);但我还在买新的东西。
我怎么能模仿IDeviceGroupDao<TDeviceGroup>
发布于 2017-11-10 11:20:23
因为DeviceGroupManagerBase是一个抽象基类,所以需要一个SUT双。如果您将DeviceGroupDao属性设置为public,那么这是最简单的
public abstract class DeviceGroupManagerBase<TDeviceGroup> where TDeviceGroup : DeviceGroup
{
public abstract IDeviceGroupDao<TDeviceGroup> DeviceGroupDao { get; }
public TDeviceGroup UpdateDeviceIndexes(Device device)
{
return DeviceGroupDao.GetDeviceGroup(device.Group.Id);
}
}否则,您将需要使用Moq的API来定义和覆盖protected成员,这是可能的,但需要做更多的工作。
然后,您需要覆盖subject的DeviceGroupDao属性:
subject.SetupGet(x => x.DeviceGroupDao).Returns(deviceGroupDaoMock.Object);下面是完整的测试:
[TestFixture]
[Category("Unit")]
public class DeviceGroupManagerBaseTests
{
private IFixture fixture;
private Mock<DeviceGroupManagerBase<DeviceGroup>> subject;
private Mock<IDeviceGroupDao<DeviceGroup>> deviceGroupDaoMock;
private DeviceGroupManagerBase<DeviceGroup> Manager => subject.Object;
[OneTimeSetUp]
public void Init()
{
fixture = new Fixture().Customize(new AutoMoqCustomization());
deviceGroupDaoMock = fixture.Freeze<Mock<IDeviceGroupDao<DeviceGroup>>>();
subject = fixture.Freeze<Mock<DeviceGroupManagerBase<DeviceGroup>>>();
subject.SetupGet(x => x.DeviceGroupDao).Returns(deviceGroupDaoMock.Object);
}
[Test]
public void TestUpdateDeviceIndexes()
{
var device = fixture.Create<Device>();
var deviceGroup = fixture.Create<DeviceGroup>();
deviceGroupDaoMock.Setup(x => x.GetDeviceGroup(It.IsAny<int>())).Returns(deviceGroup);
var result = Manager.UpdateDeviceIndexes(device);
Assert.AreEqual(deviceGroup.Id, result.Id);
}
}这东西现在传到我的机器上了。
发布于 2017-11-10 10:56:43
由于DeviceGroupDao是受保护的,所以您需要找到一种外部访问它的方法。创建一个存根,允许您设置它的值。
public class DeviceGroupManagerBaseStub<TDeviceGroup>
: DeviceGroupManagerBase<TDeviceGroup> where TDeviceGroup : DeviceGroup {
private IDeviceGroupDao<TDeviceGroup> deviceGroupDao;
public DeviceGroupManagerBaseStub(IDeviceGroupDao<TDeviceGroup> deviceGroupDao) {
this.deviceGroupDao = deviceGroupDao;
}
protected override IDeviceGroupDao<TDeviceGroup> DeviceGroupDao {
get {
return deviceGroupDao;
}
}
}然后,您可以模拟IDeviceGroupDao<TDeviceGroup>并将其插入到存根中进行测试。
https://stackoverflow.com/questions/47219510
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