同时循环在打印语句时永远重复

Question

我正在制作一个Hangman游戏，用户猜测一个颜色。我想要发生的是:如果用户不正确地获得了5以上(查看了所有的5个提示)，它将声明用户丢失了。在while循环完成之后(单词是正确的，或者经过了所有的5个提示)，它应该告诉你是否赢了。这是代码中执行以下操作的部分：

public static void main(String[] args){
  Scanner in = new Scanner(System.in);
  String color = getColor();
  String result = EmptyStr(color);
  String[] hints = getHints(color);
  System.out.println("Please enter a letter:");
  char letter = in.next().charAt(0);
//-----------------------------------------------------------
  int wrong = 0;
  while (wrong<6){
    if (checkLetter(color, letter)){
      // result was previously defined elsewhere so don't worry about it
      result = Result(color, result, letter);
      System.out.println("Correct guess! here is your word so far: " + result);
      System.out.println("Lifelines left: " + (5 - wrong));
      if (result.equals(color)){
        System.out.println("congratulations! You Won!");
        break;
      }
    }
    else{
      wrong ++;
      System.out.println(hints[0]);
      System.out.println("Lifelines left: " + (5 - wrong));
    }
  }
  // also not sure what to put here after player wins or loses: System.out.println("Sorry! You lost! The correct word was: " + color);

}

然而，一旦我输入了一个字母，并且它是正确的，result = Result(color, result, letter); System.out.println("Correct guess! here is your word so far: " + result); System.out.println("Lifelines left: " + (5 - wrong));就会永远重复。我想知道:为什么它会永远重复？而且，我怎样才能修好它才能起作用呢？

Answer 1

我发现了我自己的问题！

问题是，为了重申并允许我重新输入一个字母，char letter = in.next().charAt(0);必须在while循环中。解决了整个问题！

Answer 2

我想我明白问题了。当用户得到正确的猜测时，只有在错误的情况下，才有迭代。确保添加另一个“错误的++"，在第一个如果。也许能解决问题。

if (checkLetter(color, letter)){
      // result was previously defined elsewhere so don't worry about it
      result = Result(color, result, letter);
      System.out.println("Correct guess! here is your word so far: " + result);
      System.out.println("Lifelines left: " + (5 - wrong));
      wrong ++;