如何映射不包含数字regex的字符串内部引用

Question

我有如下的条件：

• “记录一”，“字段a”：“随机a b c"，”归档b“：”随机a b c"，“归档c":"123”
• “记录二”，“字段a”：“随机a b c"，”归档b“：”随机a b c"，“归档c":"abc”

如何从使用regex不包含任何数字的字段c中提取值？我试过这样的方法：

r"\"filed c\"\:\"([^\"\d]*)"

但它不起作用。谢谢。

Answer 1

说你有，

records = [
    '"record one","field a":"random a b c","filed b":"random a b c","filed c":"123"',
    '"record two","field a":"random a b c","filed b":"random a b c","filed c":"abc"',
    '"record ...","field a":"random a b c","filed b":"random a b c","filed c":"ab12c"',
    '"record ...","field a":"random a b c","filed b":"random a b c","filed c":""',
    '"record ...","field a":"random a b c","filed b":"random a b c","filed c":"12abc"',
    '"record nth","field a":"random a b c","filed b":"random a b c","filed c":"Xyz"',
]

做什么？

import re
rex = '"filed c":"([^\d]*)"'
does_not_contain_any_number = []
for record in records:
    q = re.compile(rex, re.DOTALL).findall(record)
    if len(''.join(q)):
        does_not_contain_any_number += q


print(does_not_contain_any_number)
#['abc', 'Xyz']