从GridViewColumn获取MouseEnter项

Question

我有ListView和GridViewColumn

<GridViewColumn Header="Name">
    <GridViewColumn.CellTemplate>
        <DataTemplate>
            <StackPanel Orientation="Horizontal"
                        MouseEnter="StackPanel_MouseEnter">
                <CheckBox  Checked="CheckBox_Checked"
                           Unchecked="CheckBox_Unchecked">
                    <CheckBox.IsChecked>
                        <Binding Path="IsSelected" RelativeSource="{RelativeSource AncestorType={x:Type ListViewItem}}"/>
                    </CheckBox.IsChecked>
                </CheckBox>
                <TextBlock x:Name="textBlock"
                           Text="{Binding Name}"/>
            </StackPanel>
        </DataTemplate>
    </GridViewColumn.CellTemplate>
</GridViewColumn>

因此，如您所见，我添加了StackPanel MouseEnter事件：

private void StackPanel_MouseEnter(object sender, MouseEventArgs e)
{

}

因此，我的问题是在这个StackPanel_MouseEnter函数中:如何获得GridViewColumn中的当前对象？(甚至是我的ListView中的当前索引)

Answer 1

通过访问堆栈面板的Name，您可以获得该行绑定到的当前项(例如绑定TextBlock的项)：

private void StackPanel_MouseEnter(object sender, MouseEventArgs e) {
    var item = ((FrameworkElement)sender).DataContext as YourItem;
    if (item != null) {
        // do stuff   
    }            
}