向量搜索中的故障分割

Question

当我试图在向量中搜索一个特定的值时，我会得到一个分割错误。向量是人的类型

struct Person{
    string name;
    string address;
    string email;
    string number;
    string SocialSec;
    string other;
};

这是我的搜索功能：

void searchContact(vector<Person> &people) {
    string searchTerm;
    cout << endl;
    cout << "Enter search term: ";
    getline(cin, searchTerm);
    vector<Person>::iterator it=find(people.begin(), people.end(), searchTerm);

    if (it != people.end()){
        cout << *it;
    }else{
        cout << "Element not found\n";
    }
}

下面是==和<<操作符的操作符重载：

ostream& operator<<(ostream &stream, const Person &it){
    stream << it;
    return stream;
}

    bool operator==(const Person &lhs, const string &rhs){
        return lhs.name == rhs;     
    }

分段错误是这样的：

Program received signal SIGSEGV, Segmentation fault.
0x00005555555565ae in operator<< (
    stream=<error reading variable: Cannot access memory at address 0x7fffff7feff8>, 
    it=<error reading variable: Cannot access memory at address 0x7fffff7feff0>) at class.cpp:114
114 ostream& operator<<(ostream &stream, const Person &it){
(gdb) 

做一个回溯：

#1  0x00005555555565c9 in operator<< (stream=..., it=...) at class.cpp:115
#2  0x00005555555565c9 in operator<< (stream=..., it=...) at class.cpp:115
#3  0x00005555555565c9 in operator<< (stream=..., it=...) at class.cpp:115
#4  0x00005555555565c9 in operator<< (stream=..., it=...) at class.cpp:115
#5  0x00005555555565c9 in operator<< (stream=..., it=...) at class.cpp:115
#6  0x00005555555565c9 in operator<< (stream=..., it=...) at class.cpp:115
#7  0x00005555555565c9 in operator<< (stream=..., it=...) at class.cpp:115
#8  0x00005555555565c9 in operator<< (stream=..., it=...) at class.cpp:115
#9  0x00005555555565c9 in operator<< (stream=..., it=...) at class.cpp:115
#10 0x00005555555565c9 in operator<< (stream=..., it=...) at class.cpp:115
#11 0x00005555555565c9 in operator<< (stream=..., it=...) at class.cpp:115
#12 0x00005555555565c9 in operator<< (stream=..., it=...) at class.cpp:115
#13 0x00005555555565c9 in operator<< (stream=..., it=...) at class.cpp:115
#14 0x00005555555565c9 in operator<< (stream=..., it=...) at class.cpp:115
#15 0x00005555555565c9 in operator<< (stream=..., it=...) at class.cpp:115
#16 0x00005555555565c9 in operator<< (stream=..., it=...) at class.cpp:115
#17 0x00005555555565c9 in operator<< (stream=..., it=...) at class.cpp:115
#18 0x00005555555565c9 in operator<< (stream=..., it=...) at class.cpp:115

为什么会发生这种事，我该怎么解决呢？是堆栈溢出吗？

编辑:在最初的帖子中添加了operator<<重载以进行澄清。

Answer 1

运算符应该打印Person类的基本类型。如下所示：

ostream& operator<<(ostream &stream, const Person &it){
    stream << "This is the name: " << it.name;
    return stream;
}

如果您确实在函数中流<<，它将继续在无限递归调用中打印Person。

Answer 2

哦，对不起，我有点弄错了。以下是我的operator<<重载：

ostream& operator<<(ostream &stream, const Person &it){
    stream << it;
    return stream;
}