JavaScript localeCompare没有很好的排序[ "aaa-1.0“、"aaa-1.1”、"aaa-1.01“、"aaa-11”、"aaa-2.01"]

Question

我想按照字符串的“十进制”数字值和字母顺序对字符串进行排序。保持它的自然秩序。

var strArray = ["aaa-0", "aaa-0.01", "aaa-1.0", "aaa-1.1", "aaa-1.01", "aaa-2.01", "bbb-2.01", "aaa-11", "aaa-2.01"]

strArray.sort(function (a, b) {
    return a.localeCompare(b,undefined, {numeric: true, sensitivity: 'base'});
});

返回：

["aaa-0", "aaa-0.01", "aaa-1.0", "aaa-1.1", "aaa-1.01", "aaa-2.01", "aaa-2.01", "aaa-11", "bbb-2.01"]

而我想要：

["aaa-0", "aaa-0.01", "aaa-1.0", "aaa-1.01", "aaa-1.1", "aaa-2.01", "aaa-2.01", "aaa-11", "bbb-2.01"]

怎么才能做到这一点呢？即使我用"，“而不是”。“分类是一样的。

Answer 1

你需要把数字和字母分开排序。

演示

​

var strArray = ["aaa-0", "aaa-0.01", "aaa-1.0", "aaa-1.1", "aaa-1.01", "aaa-2.01", "bbb-2.01", "aaa-11", "aaa-2.01"]

strArray.sort(function(a, b) {
  var splitA = a.split("-");
  var splitB = b.split("-");
  if (splitA[0] == splitB[0]) {
    return (Number(splitA[1]) - Number(splitB[1]));
  } else {
    return splitA[0].localeCompare(splitB[0], undefined, {
      numeric: true,
      sensitivity: 'base'
    });
  }
});
console.log(strArray);

​

Answer 2

您可以将参数中的标志true设置为true。

​

var array = ["aaa-0", "aaa-0.01", "aaa-1.0", "aaa-1.1", "aaa-1.01", "aaa-2.01", "bbb-2.01", "aaa-11", "aaa-2.01"]

array.sort(function(a, b) {
    return a.localeCompare(b, undefined, { ignorePunctuation: true, numeric: true, sensitivity: 'base' });
});

console.log(array);

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