检查对象中日期的顺序

Question

我试图确保在对象中输入的日期顺序符合逻辑顺序。这是我的代码：

function checkDates(pet) {
        const dates = [
            pet.birthDate,
            pet.saleDate,
            pet.acquisitionDate,
            pet.deathDate
        ].filter( (date) => {
            // filter out undefined items
            return date;
        });

        // list of dates in their chronological order
        const sortedDates = dates.slice(0).sort();

        const inOrder = dates.every( (date, i) => {
            // check to make sure entered date is the same as the chronological date
            return date === sortedDates[i];
        });

        if (!inOrder) {
            throw new ValidationError('The dates are in an illogical order');
        }
    }

问题是，saleDate和acquisitionDate不需要按照这个顺序(如日期数组中定义的那样)--它们只需要比birthDate更多，比deathDate更少。不需要不同的日期，例如，传递给我的宠物对象如下所示：

const pet = {
  name: "Sam",
  birthDate: "2017-01-01",
  acquisitionDate: "2017-02-01",
  saleDate: "2017-03-01"
}

进一步澄清:如果存在，birthDate必须总是第一位的，而deathDate必须始终是最后一位。销售和收购必须在出生和死亡日期之间(如果他们在场)，否则，出售是在收购之前还是反之亦然。

Answer 1

您在正确的路径上，但不一定需要排序：

function checkDates(pet) {
    const dates = [
        pet.birthDate,
        pet.saleDate,
        pet.acquisitionDate,
        pet.deathDate
    ].filter(date => date);

    const inOrder =
        (pet.birthDate ? dates.every(date => date >= pet.birthDate) : true) &&
        (pet.deathDate ? dates.every(date => date <= pet.deathDate) : true)

    if (!inOrder) {
        throw new ValidationError('The dates are in an illogical order');
    }
}

Answer 2

您只需迭代给定的数组，而不进行排序，因为所有日期都必须按顺序排列。

​

function check({ birthDate, acquisitionDate, saleDate, deathDate }) {
    return [birthDate, acquisitionDate, saleDate, deathDate]
        .filter(Boolean)
        .every((a, i, aa) => !i || aa[i - 1] <= a);
}

console.log(check({ name: "Sam", birthDate: "2017-01-01", acquisitionDate: "2017-02-01", saleDate: "2017-03-01" }));
console.log(check({ name: "Sam", birthDate: "2018-01-01", acquisitionDate: "2017-02-01", saleDate: "2017-03-01" }));

​

Answer 3

您是说，saleDate和acquisitionDate的顺序并不重要--它们只需要高于birthDate而低于deathDate，在这种情况下，您可以简化您的函数，只执行以下四项检查：

function checkDates(pet) {
  var birthDate = new Date(pet.birthDate);
  var saleDate = new Date(pet.saleDate);
  var acquisitionDate = new Date(pet.acquisitionDate);
  var deathDate = pet.deathDate ? new Date(pet.deathDate) : Infinity;

  var inOrder = (birthDate < saleDate) && (birthDate < acquisitionDate) && (saleDate < deathDate) && (acquisitionDate < deathDate);

  if (!inOrder) {
    throw new ValidationError('The dates are in an illogical order');
  }
}

不需要使用array，不需要排序和循环操作，它实际上是无用的。

演示：

​

function checkDates(pet) {
  var birthDate = new Date(pet.birthDate);
  var saleDate = new Date(pet.saleDate);
  var acquisitionDate = new Date(pet.acquisitionDate);
  var deathDate = pet.deathDate ? new Date(pet.deathDate) : Infinity;

  var inOrder = (birthDate < saleDate) && (birthDate < acquisitionDate) && (saleDate < deathDate) && (acquisitionDate < deathDate);

  if (!inOrder) {
    throw new ValidationError('The dates are in an illogical order');
  }
}
console.log(checkDates({
      name: "Sam",
      birthDate: "2018-01-01",
      acquisitionDate: "2017-02-01",
      saleDate: "2017-03-01"
    }));

​