点击Android onStart if按钮

Question

如果在我的onStart()上单击了一个按钮，我如何放置一个if else语句来检查单击的按钮是注册还是登录？

这是我的密码

public void onClick(View v) {
        switch (v.getId()) {
            case R.id.register:
                i = new Intent(this, RegisterCustomer.class);
                startActivity(i);
                finish();
                break;
            case R.id.login:
                final String email = memail.getText().toString();
                final String password = mpassword.getText().toString();
                mAuth.signInWithEmailAndPassword(email, password).addOnCompleteListener(CustomerLoginActivty.this, new OnCompleteListener<AuthResult>() {
                    @Override
                    public void onComplete(@NonNull Task<AuthResult> task) {
                        if (!task.isSuccessful()) {
                            Toast.makeText(CustomerLoginActivty.this, "sign in error", Toast.LENGTH_SHORT).show();
                        }
                    }
                });
                break;
        }
    }

    @Override
    protected void onStart() {
        super.onStart();
        mAuth.addAuthStateListener(firebaseAuthListener);
    }

Answer 1

1. 在类中创建一个字段。例如int clickedButton；
2. 在onStart()中，使用该字段检查id。 int clickedButton；公共无效onClick(查看v) { clickedButton = v.getId()；开关(v.getId()) { case R.id.register: i=新意图(clickedButton，RegisterCustomer.class)；startActivity(i)；finish()；中断；case R.id.login: final String email = memail.getText().toString()；最终字符串密码= mpassword.getText().toString()；password).addOnCompleteListener(CustomerLoginActivty.this，mAuth.signInWithEmailAndPassword(电子邮件，新OnCompleteListener < AuthResult > () {@覆盖公共空任务< AuthResult >任务){ if (!task.isSuccessful()) { Toast.makeText(CustomerLoginActivty.this，"sign“，Toast.LENGTH_SHORT).show()}}；}}@覆盖受保护的onStart() { super.onStart()；if(clickedButton != null){ switch (clickedButton) { case R.id.register: //do super.onStart R.id.login: //do your }}