函数的返回值被忽略

Question

VOWELS = ['a', 'e', 'i', 'o', 'u']

BEGINNING = ["th", "st", "qu", "pl", "tr"]


def pig_latin2(word):
    # word is a string to convert to pig-latin
    string = word
    string = string.lower()
    # get first letter in string
    test = string[0]
    if test not in VOWELS:
        # remove first letter from string skip index 0
        string = string[1:] + string[0]
        # add characters to string
        string = string + "ay"
    if test in VOWELS:
        string = string + "hay"
    print(string)


def pig_latin(word):
    string = word
    transfer_word = word
    string.lower()
    test = string[0] + string[1]
    if test not in BEGINNING:
        pig_latin2(transfer_word)

    if test in BEGINNING:
        string = string[2:] + string[0] + string[1] + "ay"
    print(string)

当我在上面两个函数中取消注释下面的代码并用返回字符串替换print( string )时，它只适用于pig_latin()中的单词。一旦word被传递给pig_latin2()，我就会得到所有单词和程序崩溃的值为None。

# def start_program():
    # print("Would you like to convert words or sentence into pig latin?")
    # answer = input("(y/n) >>>")
    # print("Only have words with spaces, no punctuation marks!")
    # word_list = ""
    # if answer == "y":
    #   words = input("Provide words or sentence here: \n>>>")
    #   new_words = words.split()
    #   for word in new_words:
    #       word = pig_latin(word)
    #       word_list = word_list + " " + word
    #   print(word_list)

    # elif answer == "n":
    #   print("Goodbye")
    #   quit()


    # start_program()

Answer 1

您没有捕获pig_latin2函数的返回值。所以不管这个函数做什么，你都要放弃它的输出。

修正pig_latin函数中的这一行：

if test not in BEGINNING:
    string = pig_latin2(transfer_word)  # <----------- forgot 'string =' here

当它固定的时候，它对我起作用。话虽如此，还是有一堆东西要清理。