util.inspect.defaultOptions in TypeScript

Question

在node.d.ts中，它声明为

declare module "util" {
    export function inspect(object: any, showHidden?: boolean, depth?: number | null, color?: boolean): string;
    export function inspect(object: any, options: InspectOptions): string;
}

所以我不能扩展它

我试过了

declare module 'util' {
  export interface inspect {
    defaultOptions: InspectOptions;
  }
}

但是它一直在错误地运行Property 'defaultOptions' does not exist on type '{ (object: any, showHidden?: boolean, depth?: number, color?: boolean): string; (object: any, opt...'.

Answer 1

使用namespace扩展函数。

并且它已经在@type/节点中修复了。