密码检查器UpperCase

Question

下面是我正在做的小程序

构建密码检查器。它将接受字符串输入。条件:密码字符串必须包含至少一个大写，一个小写，一个数字和长度必须是最少8个字符。否则它会说“无效密码”。

我正在尝试下面的代码

password = str(raw_input("Enter the password: "))

if password.isalnum() == False:
    print "Password should contain atleast one special character or number"
if password.isalnum() == False:
    print "Password should contain atleast one numeric number"
elif len(password)<8:
    print 'Too short'
elif password.isupper() == False:
    print 'Password should contain atleast one uppercase character'
elif password.islower() == False:
    print 'Password should contain atleast one lowercase character'
else:
    print "Password is OK"

但这是不一致的，它要求大写，即使在那里，

Enter the password: niswdgER41
Password should contain atleast one uppercase character

Answer 1

您有几个错误，但最重要的是使用检查整个字符串是否保持条件的所有方法，而不是一次它的字符。

改为：

def validate_password(pwd):
    conds = [
        lambda s: any(x.isupper() for x in s),
        lambda s: any(x.islower() for x in s),
        lambda s: any(x.isdigit() for x in s),
        lambda s: len(s) >= 8
    ]

    return all(cond(pwd) for cond in conds)

但是，如果您确实希望用户知道缺少什么，可以使用以下实现：

def validate_password(pwd):
    conds = {
        "uppercase": lambda s: any(x.isupper() for x in s),
        "lowercase": lambda s: any(x.islower() for x in s),
        "number": lambda s: any(x.isdigit() for x in s),
        "length": lambda s: len(s) >= 8
    }

    valid = True
    for name, cond in conds.iteritems():
        if not cond(pwd):
            print "Password lacking " + name
            valid = False

    if valid:
        print "Password OK"
    else
        print "Password Invalid"
    return valid

Answer 2

可以使用列表理解来检查字符串中的所有字符：

contains_upper_case_character = any([letter.isupper() for letter in password])

# contains_upper_case_character is True if password contains an uppercase letter.

如果您想将其扩展到更多的大写字母：

password = 'StrinG12'
upper_case_letters = [letter.isupper() for letter in password].count(True)

print(upper_case_letters)
>>> 2

Answer 3

def checkpassword ():
    password = input ("please enter password")




def menu ():
    print ("1. Check Password")
    print ("2. Generate Password")
    print ("3. Quit")
    optionchoice = input (" please chose a menu,1,2,3")
    if optionchoice == "1":
        checkpassword()
    elif optionchoice == "2":
        pass
    elif optionchoice == "3":
        pass
    else :
        print ("invalid answer!")
        menu()


menu()