如果没有必要，Python代码重复8次。

Question

def Reset():
    global seven_digit
    seven_digit = ["","","","","","",""]
    global x
    x = 0
    global eight
    eight = 0
    global c
    c = 0
    cinput()
def cinput():
    global thing
    print("Enter digit ", x+1)
    thing = input("")
    check()
def check():
    global eight
    global x
    if not thing.isdigit():
        print("That character is not allowed")
        cinput()
    elif len(thing) > 1:
        print("Those characters are not allowed")
        cinput()
    if x < 7:
        seven_digit[x] = int(thing)
        x += 1
        cinput()
   if x == 7:
        eight = int(thing)
        fcheck()
def fcheck(): #this section is temporary just for testing
    global c 
    c+=1
    print("This is c, ", c)
    print("Test")
    print(seven_digit)
    print(eight)
Reset()

这是我一直作为a级任务开发的代码(这是今年的GCSE课程)，但是我遇到了一个问题，在自创建函数fcheck()中的最后一部分重复了8次。我以前在python中使用过类似的过程，以前从未见过这样的错误。我想知道有没有人知道我能做些什么来解决这个问题，谢谢。

Answer 1

check和cinput之间有一个相互调用，所以在这个调用链中调用fcheck，它将被调用8次。

如果您想要调用fcheck一次，在所有的计算链之后，您可以在check的最后一行删除对它的调用，然后在Reset的末尾调用它。

def Reset():
    global seven_digit
    seven_digit = ["","","","","","",""]
    global x
    x = 0
    global eight
    eight = 0
    global c
    c = 0
    cinput()
    fcheck()

def cinput():
    global thing
    print("Enter digit ", x+1)
    thing = str(input(""))
    check()

def check():
    global eight
    global x
    if not thing.isdigit():
        print("That character is not allowed")
        cinput()
    elif len(thing) > 1:
        print("Those characters are not allowed")
        cinput()
    if x < 7:
        seven_digit[x] = int(thing)
        x += 1
        cinput()
    if x == 7:
        eight = int(thing)

def fcheck(): #this section is temporary just for testing
    global c
    c+=1
    print("This is c, ", c)
    print("Test")
    print(seven_digit)
    print(eight)

Reset()