不能通过wmic启动npm

Question

如果我在bat-file命令中放置启动node

wmic process call create "npm run go","%~dp0."

一切都很好：

D:\Temp\Supertemp\wmic npm>wmic process call create "node go","D:\Temp\Supertemp\wmic npm\."
Идет выполнение (Win32_Process)->Create()
Метод успешно вызван.
Параметры вывода:
instance of __PARAMETERS
{
        ProcessId = 13292;
        ReturnValue = 0;
};

但是如果我用npm代替

wmic process call create "npm run go","%~dp0."

发生错误9，根据msdn表示找不到路径：

D:\Temp\Supertemp\wmic npm>wmic process call create "npm run go","D:\Temp\Supertemp\wmic npm\."
Идет выполнение (Win32_Process)->Create()
Метод успешно вызван.
Параметры вывода:
instance of __PARAMETERS
{
        ReturnValue = 9;
};

文件package.json

{
  "name": "wmic-npm-test",
  "version": "0.0.0",
  "scripts": {
    "go": "node go"
  }
}

文件go.js

setInterval(function () {
  console.log(require('process').cwd());
}, 1000);

如果简单地从控制台启动npm，那么一切都能正常工作：

D:\Temp\Supertemp\wmic npm>npm run go

> wmic-npm-test@0.0.0 go D:\Temp\Supertemp\wmic npm
> node go

D:\Temp\Supertemp\wmic npm
D:\Temp\Supertemp\wmic npm

我是通过wmic 获取进程标识开始的。

PS：俄语中同样的问题。

Answer 1

有文件npm.cmd和npm文件用于sh

D:\Temp\Supertemp\wmic npm>where npm
C:\Program Files\nodejs\npm
C:\Program Files\nodejs\npm.cmd

要执行npm命令，需要指定要运行cmd-file：

wmic process call create "npm.cmd run go","%~dp0."

Answer 2

试着这样做(在我对问题的评论中的模式细节)：

@echo off

for %%a in (npm.cmd) do set "npm_path=%%~f$PATH:a"
echo %npm_path%

wmic process call create "cmd.exe /c call \"%npm_path%\" ","%~dp0."