我一直试图将来自不同表的4个或多个(*)查询转换为一个查询。
这可能吗?还是我要问四个不同的问题?
这是我的密码:
try (final PreparedStatement sel = conn.prepareStatement("SELECT COUNT(*), SUM(coins) FROM User");
final PreparedStatement sel2 = conn.prepareStatement("SELECT COUNT(*) FROM Friends");
final PreparedStatement sel3 = conn.prepareStatement("SELECT COUNT(*) FROM Clans");
final PreparedStatement sel4 = conn.prepareStatement("SELECT COUNT(*) FROM ClanMembers")) {
try (final ResultSet rs = sel.executeQuery(); final ResultSet rs2 = sel2.executeQuery(); final ResultSet rs3 = sel3.executeQuery()) {
rs.last();
rs2.last();
rs3.last();
return new Object[] { rs.getInt(1), rs.getInt(2), rs2.getInt(1) / 2, rs3.getInt(1) };
}
}发布于 2017-09-08 07:01:13
SELECT COUNT(*), SUM(coins) FROM User
union all
SELECT COUNT(*), 0 FROM Friends
union all
SELECT COUNT(*), 0 FROM Clans
union all
SELECT COUNT(*), 0 FROM ClanMembers
...对于所有联合查询,列的数量和类型必须相同。
更新答案,以显示如何组合查询。
发布于 2017-09-08 07:27:45
只需给出另一个可选的解决方案(我还不能发表评论,所以我不得不写成答案)
StanislavL的答案是一个很好的答案,你可以用它,它会返回行
但是万一你只需要1行的话,你可以试试这个
SELECT q1.count1,q1.coins,q2.count2, q3.count3, q4.count4
from (select (COUNT(*) count1, SUM(coins) coins, 1 id FROM User, 1 var) q1
inner join (SELECT COUNT(*) count2, 1 id FROM Friends) q2 on q1.id=q2.id
inner join (SELECT COUNT(*) count3, 1 id FROM Clans) q3 on q1.id=q3.id
inner join (SELECT COUNT(*) count4, 1 id FROM ClanMembers) q4 on q1.id=q4.id发布于 2017-09-08 08:42:38
看来我错过了显而易见的答案。
这解决了我的问题:
SELECT COUNT(*) FROM User union all SELECT COUNT(*) FROM Friends union all SELECT COUNT(*) FROM Clans union all SELECT COUNT(*) FROM ClanMembers union all SELECT SUM(coins) FROM User ...
https://stackoverflow.com/questions/46110419
复制相似问题