防止错误: strpos() [function.strpos]：空分隔PHP

Question

我的代码有点小问题。我有一个搜索框，它使用多个变量作为数据库进行搜索，一切运行良好，显示良好。当文本框中没有条目时，我的问题就出现了，然后我得到以下错误：

strpos() function.strpos:空分隔符

在设置变量之前，是否可以检查文本框是否为空？

这是我的密码：

if(isset($_POST["searchSub"])) {
    $searchTerm = $_POST["searchTb"];

    $pos1 = strpos($tBody1, $searchTerm);
    $pos2 = strpos($tBody2, $searchTerm);
    $pos3 = strpos($tBody3, $searchTerm);
    $pos4 = strpos($tBody4, $searchTerm);
    $pos5 = strpos($tBody5, $searchTerm);
    $pos6 = strpos($tBody6, $searchTerm);
    $pos7 = strpos($tBody7, $searchTerm);
    $pos8 = strpos($tBody8, $searchTerm);
    $pos9 = strpos($tBody9, $searchTerm);
    $pos10 = strpos($tBody10, $searchTerm);
    $pos11 = strpos($tBody11, $searchTerm);
    $pos12 = strpos($tBody12, $searchTerm);
    $pos13 = strpos($tBody13, $searchTerm);
    $pos14 = strpos($tBody14, $searchTerm);
    $pos15 = strpos($tBody15, $searchTerm);
    $pos16 = strpos($tBody16, $searchTerm);
    $pos17 = strpos($tBody17, $searchTerm);
    $pos18 = strpos($tBody18, $searchTerm);
    $pos19 = strpos($tBody19, $searchTerm);
    $pos20 = strpos($tBody20, $searchTerm);
}

Answer 1

在尝试使用该字段之前，需要确保输入了相关字段。

if(isset($_POST["searchSub"]) && !empty($_POST["searchTb"])) {
    searchTerm = $_POST["searchTb"];

    $pos1 = strpos($tBody1, $searchTerm);
    $pos2 = strpos($tBody2, $searchTerm);
    $pos3 = strpos($tBody3, $searchTerm);
    $pos4 = strpos($tBody4, $searchTerm);
    $pos5 = strpos($tBody5, $searchTerm);
    $pos6 = strpos($tBody6, $searchTerm);
    $pos7 = strpos($tBody7, $searchTerm);
    $pos8 = strpos($tBody8, $searchTerm);
    $pos9 = strpos($tBody9, $searchTerm);
    $pos10 = strpos($tBody10, $searchTerm);
    $pos11 = strpos($tBody11, $searchTerm);
    $pos12 = strpos($tBody12, $searchTerm);
    $pos13 = strpos($tBody13, $searchTerm);
    $pos14 = strpos($tBody14, $searchTerm);
    $pos15 = strpos($tBody15, $searchTerm);
    $pos16 = strpos($tBody16, $searchTerm);
    $pos17 = strpos($tBody17, $searchTerm);
    $pos18 = strpos($tBody18, $searchTerm);
    $pos19 = strpos($tBody19, $searchTerm);
    $pos20 = strpos($tBody20, $searchTerm);
}

Answer 2

只需使用空()代替isset()

Answer 3

你应该加上像turnery这样的条件。

if(isset($_POST["searchSub"]) && !empty($_POST["searchTb"])) {
$searchTerm = $_POST["searchTb"];

$pos1 = (tBody1 != "")?strpos($tBody1, $searchTerm):"NULL";
$pos2 = (tBody2 != "")?strpos($tBody2, $searchTerm):"NULL";
$pos3 = (tBody3 != "")?strpos($tBody3, $searchTerm):"NULL";
$pos4 = (tBody4 != "")?strpos($tBody4, $searchTerm):"NULL";
$pos5 = (tBody5 != "")?strpos($tBody5, $searchTerm):"NULL";
$pos6 = (tBody6 != "")?strpos($tBody6, $searchTerm):"NULL";
$pos7 = (tBody7 != "")?strpos($tBody7, $searchTerm):"NULL";
$pos8 = (tBody8 != "")?strpos($tBody8, $searchTerm):"NULL";
$pos9 = (tBody9 != "")?strpos($tBody9, $searchTerm):"NULL";
$pos10 = (tBody10 != "")?strpos($tBody10, $searchTerm):"NULL";
$pos11 = (tBody11 != "")?strpos($tBody11, $searchTerm):"NULL";
$pos12 = (tBody12 != "")?strpos($tBody12, $searchTerm):"NULL";
$pos13 = (tBody13 != "")?strpos($tBody13, $searchTerm):"NULL";
$pos14 = (tBody14 != "")?strpos($tBody14, $searchTerm):"NULL";
$pos15 = (tBody15 != "")?strpos($tBody15, $searchTerm):"NULL";
$pos16 = (tBody16 != "")?strpos($tBody16, $searchTerm):"NULL";
$pos17 = (tBody17 != "")?strpos($tBody17, $searchTerm):"NULL";
$pos18 = (tBody18 != "")?strpos($tBody18, $searchTerm):"NULL";
$pos19 = (tBody19 != "")?strpos($tBody19, $searchTerm):"NULL";
$pos20 = (tBody20 != "")?strpos($tBody20, $searchTerm):"NULL";

}

希望这是你的解决方案。:)