按范围值分组数组

Question

我有一个数组1，1，2，2，2，3，4，5，6，6，7，我可以根据范围值对数组进行分组，从而得到最终结果：

'1-3' = [1,1,2,2,2,3]; // Count is 6 '4-5' = [4,4,5]; // Count is 3 '6-7' = [6,6,6,7]; // Count is 4

Answer 1

我相信你需要的是：

function array_get_range($array, $min, $max) {
    return array_filter($array, function($element) use ($min, $max) {
       return $element >= $min && $element <= $max; 
    });
}

$array = [1,1,2,2,2,3,4,4,5,6,6,6,7];

$range13 = array_get_range($array, 1, 3); // [1, 1, 2, 2, 2, 3]
$range45 = array_get_range($array, 4, 5); // [4, 4, 5]
$range67 = array_get_range($array, 6, 7); // [6, 6, 6, 7]

Answer 2

使用范围创建一个新数组，然后遍历值和内部范围。如果当前值在范围内，则将记录添加到当前范围：

<?php
$numbers = [1,1,2,2,2,3,4,4,5,6,6,6,7];
$counts = [];
$counts[] = ["values"=> [1, 3], "records" => []]; // first value in "values" is min, second is max
$counts[] = ["values"=> [4, 5], "records" => []];
$counts[] = ["values"=> [6, 7], "records" => []];
foreach ($numbers as $number) {
    foreach ($counts as $key => &$value) {
        if ($number >= $value["values"][0] && $number <= $value["values"][1]) { // if between the range, add it to the records
            $value["records"][] = $number;
        }
    }
}
echo "<pre>";
foreach ($counts as $count) {
    echo $count["values"][0]." - ".$count["values"][1]." = ".count($count["records"])." elements<br>";
}

演示

Answer 3

我认为array_intersect()和range()与sizeof()/count()一起为这项任务做了更干净的工作。它消除了双重条件。

代码：(演示)

function count_range($array, $min, $max) {
    return sizeof(array_intersect($array, range($min, $max)));
}

$array = [1, 1, 2, 2, 2, 3, 4, 4, 5, 6, 6, 6, 7];

echo count_range($array, 1, 3);  // 6 from [1, 1, 2, 2, 2, 3]
echo count_range($array, 4, 4);  // 2 from [4, 4]
echo count_range($array, 2, 7);  // 11 from [2, 2, 2, 3, 4, 4, 5, 6, 6, 6, 7]

• range()创建一个由一个或多个连续整数组成的白名单数组。
• array_intersect()同时比较输入数组和白名单数组。
• sizeof()只是count()的别名，用于确定保留了多少元素。