Python 3列表到字典

Question

我有三个列表，我想用它们建立一个字典：

a = [a,b,c]  
b = [1,2,3]  
c = [4,5,6]  

我希望有：

{'a':1,4, 'b':2,5, 'c':3,6}

我现在能做的就是：

{'a':1,'b':2, 'c':3}

我该怎么办？

Answer 1

你可以试试这个：

a = ["a","b","c"] 
b = [1,2,3]  
c = [4,5,6]  

new_dict = {i:[j, k] for i, j, k in zip(a, b, c)}

输出：

{'b': [2, 5], 'c': [3, 6], 'a': [1, 4]}

如果您真的想要一个排序结果，可以尝试如下：

from collections import OrderedDict

d = OrderedDict()

for i, j, k in zip(a, b, c):
    d[i] = [j, k]

现在，您有一个按字母顺序排列键的OrderedDict对象。

Answer 2

检查这个:我建议的how to zip two lists into new one首先压缩b和c列表，然后再使用zip将它们映射到字典中：

a = ['a','b','c']
b = [1,2,3]
c = [4,5,6]
vals = zip(b,c)
d = dict(zip(a,vals))
print(d)

Answer 3

a = ['a','b','c']  
b = [1,2,3]  
c = [4,5,6] 

result = { k:v  for k,*v in zip(a,b,c)}

结果

print(result)