如何从文本文件中找到同一个特定的单词，并将其作为输出来表示？

Question

我有一个名为file.txt的文本文件，其中包含

A: - No such Root Directory
B: - No such Root Directory
C: - Fixed Drive
D: - Fixed Drive
E: - Removable Drive
F: - CD-ROM Drive
G: - Removable Drive
H: - No such Root Directory
I: - No such Root Directory
J: - No such Root Directory
K: - No such Root Directory
M: - No such Root Directory
N: - No such Root Directory
O: - No such Root Directory
P: - No such Root Directory
Q: - No such Root Directory
R: - No such Root Directory
S: - No such Root Directory
T: - No such Root Directory
U: - No such Root Directory
V: - No such Root Directory
W: - No such Root Directory
X: - No such Root Directory
Y: - No such Root Directory
Z: - No such Root Directory

在这个文件中，您可以注意到第5行和第7行中出现了两个单词Removable。

如果它有相同的特定单词Removable两次或三次，它需要显示输出有Removable word found multiple times。

如果它没有相同的特定单词Removable两次或三次，它需要显示输出有There is no multiple Removable word found。

对于这个输出，我运行了以下程序，

findstr /b Removable "file.txt" do ( 
echo Removable word found multiple times 
) || ( 
echo There is no multiple Removable word found 
)
pause

我知道这是错误的。但是我已经尽力了。朋友们，请纠正我。这对我会很有帮助的。

Answer 1

您应该能够使用Find /I /C "Removable"<"file.txt"来获取该文件中可移动实例的数量。你要做的就是检查那个号码。最常见的方法是通过将该命令放在for循环中读取该值。

就像命令提示符窗口中的这一行：

For /F %A In ('Find /I /C "Removable"^<"file.txt"') Do @If %A Lss 1 (Echo=There is no multiple Removable word found) Else Echo Removable word found %A times