在循环中更改随机数数组中的值

Question

我试图创建一个循环，当随机数与输入的相同索引相匹配时，值就会发生变化，并对后面的每个循环保持不变。

input = gets.chomp
tries_left = 12
while(tries_left > 0)
tries_left -= 1
computer = 4.times.map do rand(0..6) end.join

  if computer[0] == input[0]
    computer[0] = input[0]
 end
end

在上面的代码中，在第一个循环之后，存储到输入重置的值。

computer = 4.times.map do rand(0..6) end.join
 input = gets.chomp
  tries_left = 12
    while(tries_left > 0)
    tries_left -= 1

      if computer[0] == input[0]
        computer[0] = input[0]
     end

如果我像这样把计算机从循环中取出来，那么每次都会产生相同的随机数。再次，我需要它产生新的数字，每次除了什么已经匹配。

Answer 1

如果将computer设置为字符串数组，则可以对其进行freeze以防止对其进行进一步修改，然后在与索引不匹配时对计算机中的内容进行replace：

input = gets.chomp
tries_left = 12

computer = Array.new(4) { '' }
# setting the srand to 1234, the next 48 calls to 'rand(0..6)' will always
# result in the following sequence:
# 3, 6, 5, 4, 4, 0, 1, 1, 1, 2, 6, 3, 6, 4, 4, 2, 6, 2, 0, 0, 4, 5, 0, 1,
# 6, 6, 2, 0, 3, 4, 5, 2, 6, 2, 3, 3, 0, 1, 3, 0, 3, 2, 3, 4, 1, 3, 3, 3
# this is useful for testing things are working correctly,
# but take it out for 'live' code
srand 1234
while tries_left > 0
  # no need to keep iterating if we've generated all the correct values
  if computer.all?(&:frozen?)
    puts "won #{computer.inspect} in #{12 - tries_left} tries"
    break
  end

  tries_left -= 1
  computer.each.with_index do |random, index|
    # generate a new random number here unless they guessed correctly previously
    random.replace(rand(0..6).to_s) unless random.frozen?

    # if they've guessed the new random number, mark the string so they we
    # don't update it
    random.freeze if random == input[index]
  end

  puts "#{computer.inspect} has #{computer.count(&:frozen?)} correct numbers"
end

然后当您运行脚本时：

$ echo 3654 | ruby example.rb 
# ["3", "6", "5", "4"] has 4 correct numbers
# won ["3", "6", "5", "4"] in 1 tries
$ echo 3644 | ruby example.rb 
# ["3", "6", "5", "4"] has 3 correct numbers
# ["3", "6", "4", "4"] has 4 correct numbers
# won ["3", "6", "4", "4"] in 2 tries
$ echo 3555 | ruby example.rb 
# ["3", "6", "5", "4"] has 2 correct numbers
# ["3", "4", "5", "0"] has 2 correct numbers
# ["3", "1", "5", "1"] has 2 correct numbers
# ["3", "1", "5", "2"] has 2 correct numbers
# ["3", "6", "5", "3"] has 2 correct numbers
# ["3", "6", "5", "4"] has 2 correct numbers
# ["3", "4", "5", "2"] has 2 correct numbers
# ["3", "6", "5", "2"] has 2 correct numbers
# ["3", "0", "5", "0"] has 2 correct numbers
# ["3", "4", "5", "5"] has 3 correct numbers
# ["3", "0", "5", "5"] has 3 correct numbers
# ["3", "1", "5", "5"] has 3 correct numbers

Answer 2

还不太清楚你想要实现什么，但以下是：

if computer[0] == input[0]
  computer[0] = input[0]
end

很明显是个笨蛋。没有任何更新，因为computer[0]，无论是什么，都被设置为与以前相同的值。我相信您希望在数组中以某种方式使用索引：

4.times.map do |index|
  value = rand(0..6)
  # somehow check the similarity, e.g.:
  if input[index] == value
    # do something
  end
end

请原谅这个非常含糊的回答，但是很难理解你想要达到的目标。