如何将字符串30-Jul-17转换为日期格式07/30/17
发布于 2017-08-09 15:32:24
我不相信在VFP中有一个用来解析缩写的月份字符串(甚至是完整的月份名称)的内置方式。如果是我的话,我会为每个简短的月使用一个CASE语句,如下所示。
lcStringDate = "30-Jul-17"
lcDay = LEFT(lcStringDate, 2)
lcMonth = SUBSTR(lcStringDate, 4, 3)
lcYear = "20"+RIGHT(lcStringDate, 2)
*!* Here you'd need to have code to convert abbreviated
*!* month to a numeric month
DO CASE
CASE lcMonth = "Jan"
lcNumericMonth = "1"
CASE lcMonth = "Feb"
lcNumericMonth = "2"
.
.
.
ENDCASE
?CTOD(lcNumericMonth+"/"+lcDay+"/"+lcYear)
*!* this would output "07/30/17" if SET CENTURY is OFF
*!* this would output "07/30/2017" if SET CENTURY is ON发布于 2017-08-09 15:59:23
为了稍微扩展Steve提供的内容,您可以将其作为一个函数并反复调用.
lcDate = "30-Jul-17"
? DMYToDate( lcDate )
lcDate = "15-August-17"
? DMYToDate( lcDate )
lcDate = "29-Feb-17" && No such feb 29, 2017
? DMYToDate( lcDate )
lcDate = "32-Mar-17" && no month 32 days
? DMYToDate( lcDate )
FUNCTION DMYToDate
LPARAMETERS lcTryDate
local lnDay, lnYear, lcMonth, tmpDate, ldNewDate
lnDay = INT( VAL( LEFT( lcTryDate, 2 )))
lnYear = 2000 + INT(VAL(RIGHT( lcTryDate, 2 )))
lcMonth = SUBSTR( lcTryDate, 4, 3 )
*/ Cycle through each month with arbitrary start date...
tmpDate = DATE(2000,1,1)
DO WHILE YEAR( tmpDate ) < 2001
IF ATC( lcMonth, CMONTH( tmpDate ) ) = 1
EXIT
ENDIF
tmpDate = GOMONTH( tmpDate, 1 )
ENDDO
IF YEAR( tmpDate ) > 2000
*/ No such month found, return empty date.
RETURN CTOD( "" )
ENDIF
TRY
ldNewDate = DATE( lnYear, MONTH( tmpDate ), lnDay )
CATCH
ldNewDate = CTOD( "" )
ENDTRY
RETURN ldNewDate
ENDFUNC发布于 2017-08-18 18:03:12
试试这个:
"a“是您的日期字符串。
DATE(2000+VAL(SUBSTR(a,8,2)),int((AT(SUBSTR(UPPER(a),4,3),"JANFEBMARAPRMAYJUNJULAUGSEPOCTNOVDEC")-1)/3)+1,VAL(SUBSTR(a,1,2)))https://stackoverflow.com/questions/45594563
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