PHP/CURL/JSON:将项分配给var

Question

我有这个PHP代码，它可以100%工作，并显示以下结果，但是我如何使用这些数据作为单独的项目呢？

我习惯于使用这样的东西：

$title = $data['selection3']['name']; 
echo $title

但这在这里行不通。我希望能够分离每个项目，并为它分配一个var，这样我就可以用它构建一个广告。

PHP Curl代码：

<?php
    function origin($projecttoken,$apikey,$format) {
        $ch = curl_init();
        $apiuri = 'https://www.parsehub.com/api/v2/projects/'.$projecttoken.'/last_ready_run/data?api_key='.$apikey.'&format='.$format.'';
        curl_setopt($ch, CURLOPT_URL, $apiuri);
        curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
        curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
        curl_setopt($ch,CURLOPT_ENCODING, '');
            if(curl_exec($ch) === false){
                echo curl_error($ch) . '<br />';
            }
        $data = curl_exec($ch);
        curl_close($ch);
        return($data);
    }
?>

    <pre>
    <?php
    print_r(origin('xxxxxx','xxxxxx','json'));
    ?>
    </pre>

结果：

    {
 "selection3": [
  {
   "name": "Medal of Honor™ Pacific Assault",
   "url": "https://www.origin.com/usa/en-us/store/medal-of-honor/medal-of-honor-pacific-assault/standard-edition"
  },
  {
   "name": "Join the Fight for Freedom"
  },
  {
   "name": "This World War II shooter is On the House and yours to own totally free."
  },
  {
   "name": "FREE"
  },
  {
   "name": "Get It Now",
   "url": ""
  }
 ],
 "selection6": [
  {
   "name": "Battlefield 4™ Dragon's Teeth",
   "url": "https://www.origin.com/usa/en-us/store/battlefield/battlefield-4/expansion/battlefield-4-dragons-teeth"
  },
  {
   "name": "Upgrade Your Fight"
  },
  {
   "name": "Add this expansion to your library for free and dominate the battlefield. It's On the House! (Requires base game to play.)"
  },
  {
   "name": "FREE"
  },
  {
   "name": "Get It Now",
   "url": ""
  }
 ]
}   

Answer 1

这个结果在JSON中。使用函数json_decode()将字符串解码为数组。THen您可以定期访问它的值。

示例：

$data = json_decode($result, true);
echo $data["selection3"]["name"];

..。其中$result表示未知的结果字符串。

Answer 2

您使用循环单个数据，如下所示：

<?php
  $data = origin('xxxxxx','xxxxxx','json');
  $dataArray = json_decode($data, true);
  if(!empty($dataArray){
    foreach($dataArray as $key => $val){
      $item = $dataArray[$key];
      echo "<pre>". json_decode($item);
      //$item['name'], $item['url']
    }
  }
?>