使用php fails (xampp环境)将表单数据发送到mysqli dtbs
使用php fails (xampp环境)将表单数据发送到mysqli dtbs
提问于 2017-07-31 09:34:36
下面是我的html表单代码:问题是我无法弄清楚如何使用xampp成功地将表单提交给mysql dtbs。(数据未发送到dtb)。
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<title>My Form</title>
<meta name="description" content="An interactive form">
</head>
<body>
<form action="test.php" method="post" id="Personalinfo">
<label for="fname">Όνομα:</label>
<input type="text" id="fname" name="firstname" placeholder="Όνομα
Πελάτη..">
<input type="submit" value="Submit">
</body>
</html>现在我的php代码：
<?php
$servername = "localhost";
$username = "username";
$password = "";
$dbname = "mydb";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "INSERT INTO Guests (firstname)
VALUES ('?')";
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
?>数据不是在mysql dtb中发送的！我已经试了两天解决这个问题，但什么也没有.请帮帮忙！
你好，萨诺斯
回答 2
Stack Overflow用户
回答已采纳
发布于 2017-07-31 09:41:03
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<title>My Form</title>
<meta name="description" content="An interactive form">
</head>
<body>
<form action="test.php" method="post" id="Personalinfo">
<label for="fname">Όνομα:</label>
<input type="text" id="fname" name="firstname" placeholder="Όνομα
Πελάτη..">
<input type="submit" name="submitForm" value="Submit">
</body>
</html>
**test.php file**
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "mydb";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
if(isset($_POST['submitForm'])){
$firstname = $_POST['firstname'];
$sql = "INSERT INTO Guests (firstname)
VALUES ('{$firstname}')";
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
}else{
echo "Are you sure you enter a firstname and the name of your html submit is submitForm";
}
$conn->close();
?>Stack Overflow用户
发布于 2017-07-31 09:41:31
$sql = "INSERT INTO Guests (firstname) VALUES ('?')";“？”是在整数、字符串、双值或blob值中替换。
你放置了“？”，但忘了用bind_param来准备它。更重要的是，您必须将$firstname值传递给$stmt->bind_param("s", $firstname);。
更新代码
$firstname = $_POST['firstname'];
$sql = $conn->prepare("INSERT INTO Guests (firstname) VALUES (?)");
$sql->bind_param("s", $firstname);
if ($sql->execute() === TRUE) {读
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原文链接：
https://stackoverflow.com/questions/45412211
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