我想使用Android将安卓应用程序的演示从java转换为kotlin。但我犯了一些错误。
一些Java代码是:
public static class FileServerAsyncTask extends AsyncTask<Void, Void, String> {
private boolean isname=true;
private String name="啦啦啦";
private Context context;
private TextView statusText;
Handler myhandler=new Handler(){
@Override
public void handleMessage(Message msg) {
switch (msg.what){
case 10:
statusText.setText("XXXXX");
}
}
};
/**
* @param context
* @param statusText
*/
public FileServerAsyncTask(Context context, View statusText) {
this.context = context;
this.statusText = (TextView) statusText;
}Studio将它们转换为
class FileServerAsyncTask
/**
* @param context
* *
* @param statusText
*/
(private val context: Context, statusText: View) : AsyncTask<Void, Void, String>() {
private val isname = true
private var name = "啦啦啦"
private var statusText: TextView
init {
this.statusText = statusText as TextView
}
internal var myhandler = object : Handler() {
override fun handleMessage(msg: Message) {
when (msg.what) {
10 -> statusText.setText("XXXXX")
else -> {
}
}
}
}但是在10 -> statusText.setText("XXXXX")上也有错误
我将其更改为10 -> statusText.text = "XXXX",但错误仍然存在。然而,在同一文件中的其他句子是可以的。
怎么了?
发布于 2017-07-21 06:44:24
(private val context: Context, statusText: TextView) : AsyncTask<Void, Void, String>() {
private val isname = true
private val name = "啦啦啦"
private val statusText: TextView
internal var myhandler: Handler = object : Handler() {
override fun handleMessage(msg: Message) {
when (msg.what) {
10 -> statusText.text = "XXXXXX"
}
}
}
init {
this.statusText = statusText as TextView
}
override fun doInBackground(vararg params: Void): String? {
return null
}
}问题是构造函数将视图更改为textview。
https://stackoverflow.com/questions/45230484
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