在计时器事件中,我希望再次使组件可见。有什么不同的方法来完成这个任务吗?我给她戴上了吊带。
HTML标记:在这个文件中,我创建了警报栏
<div Class="row" wicket:id="alert_app" >
<div class="alert alert-info" role="alert" style="top: 2%; left: 50%; position: absolute;">
<a href="#" wicket:id="alert" style="color:red" >Alert - Match Found</a>
</div>
</div> Java :我实例化了WebMarkupContainer并使其在初始阶段变得不可见,在5秒警报栏出现后(这是我的计划),我使用了Timer,并在timer事件中卡住了。
WebMarkupContainer informationBox = new WebMarkupContainer("alert_app");
add(informationBox);
final AjaxLink saveProfile = new AjaxLink("alert") {
private static final long serialVersionUID = 1L;
public void onClick(AjaxRequestTarget target) {
this.setResponsePage(ABC.class);
}
};
informationBox.add(saveProfile);
informationBox.setVisible(false);
Timer timer = new Timer();
timer.schedule(new TimerTask() {
@Override
public void run() {
informationBox.setVisibilityAllowed(true);
informationBox.setVisible(true); // I got error in this line
}
}, 5000);错误:
12:37:04,735 INFO
[org.apache.wicket.response.filter.AjaxServerAndClientTimeFilter] (http-
localhost-127.0.0.1-8080-4) 1ms server time taken for request
wicket/bookmarkable/xyz.abc.vbn.class?
4&username=user+name response size: 9386
12:37:09,736 ERROR [stderr] (Timer-3) Exception in thread "Timer-3"
org.apache.wicket.WicketRuntimeException: No RequestCycle is currently set!
12:37:09,736 ERROR [stderr] (Timer-3) at
org.apache.wicket.Component.getRequest(Component.java:1791)
12:37:09,736 ERROR [stderr] (Timer-3) at
org.apache.wicket.markup.html.WebPage.dirty(WebPage.java:334)
12:37:09,736 ERROR [stderr] (Timer-3) at
org.apache.wicket.Page.dirty(Page.java:248)
12:37:09,736 ERROR [stderr] (Timer-3) at
org.apache.wicket.Page.componentStateChanging(Page.java:937)
12:37:09,736 ERROR [stderr] (Timer-3) at
org.apache.wicket.Component.addStateChange(Component.java:3512)
12:37:09,736 ERROR [stderr] (Timer-3) at
org.apache.wicket.Component.setVisible(Component.java:3195)
12:37:09,736 ERROR [stderr] (Timer-3) at
java.util.TimerThread.mainLoop(Timer.java:555)
12:37:09,736 ERROR [stderr] (Timer-3) at
java.util.TimerThread.run(Timer.java:505)发布于 2017-07-19 12:01:14
您不能只使用java.util.Timer。它启动一个不是HTTP线程的新线程,因此WicketFilter没有机会设置ThreadLocal(应用程序、会话和RequestCysle)。
您必须使用org.apache.wicket.ajax.AbstractAjaxTimerBehavior代替。在给定的持续时间之后,它将触发一个新的Ajax请求,一切都将如预期的那样工作!
发布于 2017-07-19 11:45:43
我不确定,但我看不出代码
informationBox.setOutputMarkupId(true);
informationBox.setOutputMarkupPlaceholderTag(true)发布于 2017-07-21 11:55:10
我把我的答案放在这里,这样它可以帮助观众,谢谢@阿列克谢和马丁,你们俩的回答很有帮助。
WebMarkupContainer informationBox = new WebMarkupContainer("alert_app");
informationBox.add(new AjaxLink("alert1"){
@Override
public void onClick(AjaxRequestTarget target) {
// TODO Auto-generated method stub
this.setResponsePage(ABC.class);
} });
add(informationBox);
informationBox.setOutputMarkupId(true);
informationBox.setOutputMarkupPlaceholderTag(true);
informationBox.setVisible(false);
this.add(new AbstractAjaxTimerBehavior(Duration.seconds(5))
{
private static final long serialVersionUID = 1L;
@Override
protected void onTimer(AjaxRequestTarget target)
{
target.add(informationBox.setVisible(true));
System.out.println("on timer");
stop(target);
}
});https://stackoverflow.com/questions/45188579
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