我正在尝试使用以下脚本从Sentinel-2图像集合中删除带云的图像:
// Remove images with clouds
var cloud_removal = function(image){
// save the quality assessment band QA60 as a variable
var cloud_mask = image.select('QA60');
// calculate the sum of the QA60-Band (because QA60 != 0 means cloud or cirrus presence)
var cloud_pixels = cloud_mask.reduceRegion( // reduceRegion computes a single object value pair out of an image
{reducer:ee.Reducer.sum(), // calculates the sum of all pixels..
geometry:aoi, // inside the specified geometry
scale:60}) // at this scale (matching the band resolution of the QA60 band)
.getNumber('QA60'); // extracts the values as a number
return ee.Algorithms.If(cloud_pixels.eq(0), image);
};
var s2_collection_noclouds = s2_collection_clipped.map(cloud_removal, true);
print('The clipped Sentinel-2 image collection without cloudy images: ', s2_collection_noclouds);问题是输出("s2_collection_noclouds")是一个ee.FeatureCollection。我已经尝试将输出转换为图像集合,但它仍然是一个特征集合:
var s2_collection_noclouds = ee.ImageCollection(s2_collection_clipped.map(cloud_removal, true));我遗漏了什么?
发布于 2020-08-29 07:08:44
结果对象实际上是一个图像集合,并且可以显示在地图上。例如:
var visualization = {
min: 0,
max: 3000,
bands: ['B4', 'B3', 'B2'],
};
Map.addLayer(s2_collection_noclouds.median(), visualization, "Sentinel-2")附注:我确实看到地球引擎代码编辑器控制台将对象类型标记为"FeatureCollection“,并且集合包含图像对象的功能。这似乎是因为映射函数中的ee.Algorithms.If()为多云图像返回了一个空对象。如果您返回的是一个屏蔽的图像:
return ee.Algorithms.If(cloud_pixels.eq(0), image, image.mask(0));则该集合被正确地描述为ImageCollection。
https://stackoverflow.com/questions/63616940
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