返回第一个在javascript多级嵌套对象数组中包含特定值的对象
返回第一个在javascript多级嵌套对象数组中包含特定值的对象
提问于 2017-07-15 11:47:12
我有一个对象，它包含按工作日嵌套和分组的任务。我不能改变它的结构。返回第一个任务的最佳方式是什么，即该任务的“状态”键!==“完成”的值。
{
"total_resource_cost":"20.0",
"total_unassigned_tasks_count":0,
"tasks":[
{
"unassigned_tasks_count":0,
"resource_cost":"9.0",
"weekday":"Tuesday",
"date":"2017-07-11",
"tasks":[
{
"id":6196,
"title":null,
"category":"Guest Ready Clean",
"status":"new",
"date":"2017-07-11",
"due_date":null,
"assigned_to":{
"name":"David",
"id":2,
"mobile":"",
"teams":[
]
},
"assigned_to_2":{
"name":"David",
"id":2,
"mobile":"",
"teams":[
]
},
"assigned_to_id":2,
"assigned_to_2_id":2,
"team":null,
"description":null,
"property":{
"id":114,
"code":"WEB-1",
"lat":"51.45625339999999",
"lng":"-0.16253770000002987",
"postal_code":"SW11 6SF"
},
"list":null,
"priority":3,
"created_by":null,
"created_at":"2017-07-11T16:39:34.944Z",
"updated_at":"2017-07-14T14:08:07.082Z",
"updated_by":{
"id":2,
"name":"David",
"teams":[
]
},
"notes":null,
"trigger_rule":"Booking followed by booking.",
"obsolete":true,
"resource_cost":"3.0"
},
{
"id":6228,
"title":null,
"category":"Owner Leaving Clean",
"status":"new",
"date":"2017-07-11",
"due_date":null,
"assigned_to":{
"name":"David the Housekeeper",
"id":220,
"mobile":"",
"teams":[
]
},
"assigned_to_2":{
"name":"David",
"id":2,
"mobile":"",
"teams":[
]
},
"assigned_to_id":220,
"assigned_to_2_id":2,
"team":null,
"description":null,
"property":{
"id":245,
"code":"ROL-1",
"lat":"51.51190219999999",
"lng":"-0.03558299999997416",
"postal_code":"E14 7JA"
},
"list":null,
"priority":3,
"created_by":null,
"created_at":"2017-07-11T16:39:39.895Z",
"updated_at":"2017-07-14T14:07:58.565Z",
"updated_by":{
"id":2,
"name":"David",
"teams":[
]
},
"notes":null,
"trigger_rule":"Booking following block.",
"obsolete":true,
"resource_cost":"2.5"
},
{
"id":6207,
"title":null,
"category":"Guest Ready Clean",
"status":"new",
"date":"2017-07-11",
"due_date":null,
"assigned_to":{
"name":"David the Housekeeper",
"id":220,
"mobile":"",
"teams":[
]
},
"assigned_to_2":{
"name":"David",
"id":2,
"mobile":"",
"teams":[
]
},
"assigned_to_id":220,
"assigned_to_2_id":2,
"team":null,
"description":null,
"property":{
"id":126,
"code":"PRO-1",
"lat":"51.5375129",
"lng":"-0.042265000000043074",
"postal_code":"E9 7DS"
},
"list":null,
"priority":3,
"created_by":null,
"created_at":"2017-07-11T16:39:35.963Z",
"updated_at":"2017-07-14T14:07:54.920Z",
"updated_by":{
"id":2,
"name":"David",
"teams":[
]
},
"notes":null,
"trigger_rule":"Booking followed by booking.",
"obsolete":true,
"resource_cost":"2.0"
},
{
"id":6202,
"title":null,
"category":"Guest Ready Clean",
"status":"new",
"date":"2017-07-11",
"due_date":null,
"assigned_to":{
"name":"David",
"id":2,
"mobile":"",
"teams":[
]
},
"assigned_to_2":{
"name":"David the Housekeeper",
"id":220,
"mobile":"+",
"teams":[
]
},
"assigned_to_id":2,
"assigned_to_2_id":220,
"team":null,
"description":null,
"property":{
"id":234,
"code":"CAD-2",
"lat":"51.4924164",
"lng":"-0.16394930000001295",
"postal_code":"SW3 2PP"
},
"list":null,
"priority":3,
"created_by":null,
"created_at":"2017-07-11T16:39:35.307Z",
"updated_at":"2017-07-14T14:07:49.911Z",
"updated_by":{
"id":2,
"name":"David",
"teams":[
]
},
"notes":null,
"trigger_rule":"Booking followed by booking.",
"obsolete":true,
"resource_cost":"1.5"
}
]
},
{
"unassigned_tasks_count":0,
"resource_cost":"11.0",
"weekday":"Wednesday",
"date":"2017-07-12",
"tasks":[
{
"id":6148,
"title":null,
"category":"Guest Ready Clean",
"status":"new",
"date":"2017-07-12",
"due_date":null,
"assigned_to":{
"name":"David",
"id":2,
"mobile":"",
"teams":[
]
},
"assigned_to_2":null,
"assigned_to_id":2,
"assigned_to_2_id":null,
"team":null,
"description":null,
"property":{
"id":116,
"code":"SAR-1",
"lat":null,
"lng":null,
"postal_code":null
},
"list":null,
"priority":3,
"created_by":null,
"created_at":"2017-07-11T16:39:28.736Z",
"updated_at":"2017-07-14T15:30:15.665Z",
"updated_by":{
"id":2,
"name":"David",
"teams":[
]
},
"notes":null,
"trigger_rule":"Booking followed by booking.",
"obsolete":true,
"resource_cost":"5.5"
},
{
"id":6193,
"title":null,
"category":"Guest Ready Clean",
"status":"new",
"date":"2017-07-12",
"due_date":null,
"assigned_to":{
"name":"David",
"id":2,
"mobile":"",
"teams":[
]
},
"assigned_to_2":null,
"assigned_to_id":2,
"assigned_to_2_id":null,
"team":null,
"description":null,
"property":{
"id":216,
"code":"MAC-1",
"lat":"51.5480904",
"lng":"-0.11545330000001286",
"postal_code":"N7 8QY"
},
"list":null,
"priority":3,
"created_by":null,
"created_at":"2017-07-11T16:39:34.435Z",
"updated_at":"2017-07-14T15:30:03.989Z",
"updated_by":{
"id":2,
"name":"David",
"teams":[
]
},
"notes":null,
"trigger_rule":"A stay has ended. Unclear what the next event is.",
"obsolete":true,
"resource_cost":"3.5"
},
{
"id":6238,
"title":null,
"category":"Guest Ready Clean",
"status":"new",
"date":"2017-07-12",
"due_date":null,
"assigned_to":{
"name":"David",
"id":2,
"mobile":"",
"teams":[
]
},
"assigned_to_2":null,
"assigned_to_id":2,
"assigned_to_2_id":null,
"team":null,
"description":null,
"property":{
"id":252,
"code":"WEL-1",
"lat":"51.4853737",
"lng":"0.03197999999997592",
"postal_code":"SE7 7PH"
},
"list":null,
"priority":3,
"created_by":null,
"created_at":"2017-07-11T16:39:40.933Z",
"updated_at":"2017-07-14T15:29:53.195Z",
"updated_by":{
"id":2,
"name":"David",
"teams":[
]
},
"notes":null,
"trigger_rule":"Booking followed by booking.",
"obsolete":true,
"resource_cost":"2.0"
}
]
}
]
}回答 2
Stack Overflow用户
回答已采纳
发布于 2017-07-15 12:01:39
比阿菲舍克·索尼的回答稍微好一点。我们可以使用.find返回数组中返回true的第一项，而不是对所有完成的任务进行过滤。
const firstCompletedTasked = response.tasks[0].tasks.find(task => task.status === 'complete');Stack Overflow用户
发布于 2017-07-15 11:51:14
假设您将该对象保存在名为response的变量中
let firstInCompleteTask = response.tasks[0].tasks.filter((task)=>{
return task.status !== 'complete'
})[0];另外，第一个tasks数组有两个对象，然后在其中包含一个任务数组。上面的代码从第一个对象返回第一个不完全任务。
如果希望两个对象的任务都不完整，则必须使用以下内容：
let incompleteTasks = [];
for(i = 0; i < response.tasks.length; i++){
let firstInCompleteTask = response.tasks[i].tasks.filter((task)=>{
return task.status !== 'complete'
})[0];
incompleteTasks.push(fistInCompleteTask);
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/45117834
复制相关文章
相似问题
腾讯云开发者
Copyright © 2013 - 2026 Tencent Cloud. All Rights Reserved. 腾讯云 版权所有
深圳市腾讯计算机系统有限公司 ICP备案/许可证号：粤B2-20090059 
粤公网安备44030502008569号
腾讯云计算（北京）有限责任公司 京ICP证150476号 | 京ICP备11018762号