我正在使用MappedByteBuffer将记录写入文件。下面是我的密码。当我增加要编写的BufferOverflowException时,它会抛出numberOfRows。它适用于1000万numberOfRows。如果我把numberOfRows提高到1亿,那就是扔BufferOverlowException!?
public static void writeOneFile() throws IOException{
File file = File.createTempFile("outputfile", ".txt", new File("C:\\Data\\Output"));
//f.delete();
RandomAccessFile fileAccess = new RandomAccessFile(file, "rw");
FileChannel fileChannel = fileAccess.getChannel();
long bufferSize = (long) (Math.pow(10240, 2));//(long)(Math.pow(30720, 2));//(long) (Math.pow(1024, 2));//(long)Integer.MAX_VALUE;
MappedByteBuffer mappedBuffer = fileChannel.map( FileChannel.MapMode.READ_WRITE, 0, bufferSize );
long startPosMappedBuffer = 0;
long million = 1000000;
long numberOfRows = million * 100; //million * 200 ;//1000;//million * 200 ; //200 million
long startTime = System.currentTimeMillis();
long counter = 1;
//byte[] messageBytes = (counter+"").getBytes(Charset.forName("UTF-8"));
//long bufferSize = (counter + "\n").getBytes(Charset.forName("UTF-8")).length * 1000;
while(true)
{
if( !mappedBuffer.hasRemaining() )
{
startPosMappedBuffer += mappedBuffer.position();
mappedBuffer = fileChannel.map( FileChannel.MapMode.READ_WRITE, startPosMappedBuffer, bufferSize );
}
mappedBuffer.put( (counter + System.lineSeparator()).getBytes(Charset.forName("UTF-8")) ); //+ System.lineSeparator() //putLong( counter ); // );
//mappedBuffer.rewind();
counter++;
if( counter > numberOfRows )
break;
}
fileAccess.close();
long endTime = System.currentTimeMillis();
long actualTimeTaken = endTime - startTime;
System.out.println( String.format("No Of Rows %s , Time(sec) %s ", numberOfRows, actualTimeTaken / 1000f) ) ;
}有什么提示吗?
编辑1:异常问题得到解决,并按以下方式回答。
编辑2:关于性能的最佳选择。
@EJP:下面是在DataOutputStream中使用BufferedOutputStream的代码。
static void writeFileDataBuffered() throws IOException{
File file = File.createTempFile("dbf", ".txt", new File("C:\\Output"));
DataOutputStream out = new DataOutputStream(new BufferedOutputStream(new FileOutputStream( file )));
long counter = 1;
long million = 1000000;
long numberOfRows = million * 100;
long startTime = System.currentTimeMillis();
while(true){
out.writeBytes( counter + System.lineSeparator() );
counter++;
if ( counter > numberOfRows )
break;
}
out.close();
long endTime = System.currentTimeMillis();
System.out.println("Number of Rows: "+ numberOfRows + ", Time(sec): " + (endTime - startTime)/1000f);
}.谢谢
发布于 2017-07-16 10:11:07
在做了一些背景工作之后,我找到了根本原因。我声明的bufferSize小于我正在编写的内容长度。
1亿条记录所需的字节数是: 988888898,而(long)的bufferSize (Math.pow(10240,2))是: 104857600。bufferSize短于884031298字节。正如异常所指示的那样,这是导致问题的原因。
bufferSize也可以用作Integer.MAX_VALUE,而不是计算正在写入的内容大小。尽管这会增加文件大小,但根据我的试运行结果,它不会对程序的性能产生任何影响。
.
谢谢
https://stackoverflow.com/questions/45115301
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