我有一个sql查询,我正试图将其转换为Opaleye。
我将简化我的代码,将重点放在我的问题上,即如何使用Opalyee进行模糊搜索。
Haskell (有一些现有的Opaleye结构)是
namesTable :: O.Table NamesColumnWrite NamesColumnRead
namesTable = O.Table "names" (pNames Names { id = O.optional "id"
, licenseNumber = O.required "license_number"
, fullName = O.required "full_name"
})
import qualified Database.PostgreSQL.Simple as PGS
data Names' id' licenseNumber' fullName' =
Names
{ id :: id'
, licenseNumber :: licenseNumber'
, fullName :: fullName'
} deriving (Show, Eq)
namesQuery :: Query NamesColumnRead
namesQuery = queryTable NamesTable
type NamesRead = Names' Int String String
type NamesWrite = Names' (Maybe Int) String String
type NamesColumnWrite = Names' (Maybe (O.Column O.PGInt4)) (O.Column O.PGText) (O.Column O.PGText)
type NamesColumnRead = Names' (O.Column O.PGInt4) (O.Column O.PGText) (O.Column O.PGText)
getNamesByFuzzyLicenseNumber :: PGS.Connection -> String -> IO [NamesRead]
getNamesByFuzzyLicenseNumber conn licNumber = do
let query' = "SELECT id, license_number, full_name FROM get_names_by_fuzzy_license_number_fn(?)"
PGS.query conn query' [licNumber]而Sql是
CREATE OR REPLACE FUNCTION get_names_by_license_number_fuzzy_fn(p_license_number VARCHAR)
RETURNS TABLE
(id INT
,license_number VARCHAR
,full_name TEXT
)
AS $$
SELECT
id,
license_number,
full_name
FROM names
WHERE license_number LIKE '%' || p_license_number || '%'
$$
LANGUAGE sql;所谓“模糊搜索”,我指的是搜索任何包含搜索参数p_license_number值作为子字符串的许可号的行。
如何将此模糊搜索查询转换为Opaleye?
这将涉及删除Sql文件并将getNamesByLicenseNumber替换为Haskell。我想答案可能是
getNamesByLicenseNumber :: String -> Query NamesColumnRead
getNamesByLicenseNumber licNumber = proc () -> do
names <- namesQuery -< ()
restrict -< pgString licNumber .== licenseNumber (names :: NamesColumnRead)
returnA -< names除了模糊而不是严格的匹配。
发布于 2017-07-16 15:56:07
我不知道你的问题到底是什么,因为你的问题看上去很好。有两件事我会改进的。首先,将字符串作为参数传递给QueryArr,而不是函数参数。其次,使用like而不是.==。
getNamesByLicenseNumber :: QueryArr (Column PGText) NamesColumnRead
getNamesByLicenseNumber = proc licNumber -> do
names <- namesQuery -< ()
restrict -< licNumber `like` licenseNumber (names :: NamesColumnRead)
returnA -< names这能做你想做的事吗?
https://stackoverflow.com/questions/45024640
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