ZendFramework2通过TableGateway对象更新查询

Question

public function update($table, $where = array(), $data_arr = array()){

    print_r($data_arr);

    $adapter = $this->tableGateway->getAdapter();

    $projectTable;

    if($table != null){
        $projectTable = new TableGateway($table, $adapter);
    }else{
        $projectTable = new TableGateway('account_master', $adapter);
    }
    echo "158";

    try {
        echo "123";
        $rowset = $projectTable->update(function(Update $update) use ($where, $data_arr) {

                $update->set(array('statement_no' => '01010'));

                $update->where($where);

            echo $update->getSqlString();
        });
    } catch (\Exception $e) {
            print_r($e);
    }

    print_r($rowset);
    die();
}

输出输出: 158123 --它给我传递作为参数传递的set()函数中的pass数组。此外，我还尝试将对象转换为数组((arrya)$objetc)，但它对我来说并不适用。

[10-Jul-2017 05:11:34 America/Denver] PHP Catchable fatal error:  Argument 1 passed to Zend\Db\Sql\Update::set() must be of the type array, object given, called in /home2/flywing1/vendor/zendframework/zend-db/src/TableGateway/AbstractTableGateway.php on line 336 and defined in /home2/flywing1/vendor/zendframework/zend-db/src/Sql/Update.php on line 93

Answer 1

您可以通过实现Zend\Db\Sql\Update对象来做到这一点。您可以使用TableGateway创建该对象。您应该能够在您的模型中执行以下操作

public function update($set, $where)
{
    // Here is the catch  
    $update = $this->tableGateway->getSql()->update();
    $update->set($set);
    $update->where($where);

    // Execute the query
    return $this->tableGateway->updateWith($update);
}

Answer 2

试试看，我有同样的问题，我试过这个，而且成功了。

$rowset = $projectTable->update(array('statement_no' => '01010'), $where);