我需要使用jq将这个输入转换成一个未嵌套的对象。在Python中,我可以正确地转换它,如下所示。
output = {(k1 + '-' + k2): v2 for k1, v1 in input.iteritems() for k2, v2 in v1.iteritems()}但我不知道如何在jq中做到这一点。在嵌套对象上操作的文档非常糟糕。
{
"group1-permission": {
"address": "test1",
"others": "test2",
"packet-capture": "test3",
"policy": "test4",
"schedule": "test5",
"service": "test6"
},
"group2-permission": {
"config": "none",
"data-access": "none",
"report-access": "none",
"threat-weight": "none"
},
"group3-permission": {
"antivirus": "none",
"application-control": "none",
"casi": "none",
"data-loss-prevention": "none",
"dnsfilter": "none",
"icap": "none",
"ips": "none",
"spamfilter": "none",
"voip": "none",
"waf": "none",
"webfilter": "none"
}
}输出应该如下所示:
{
"group1-permission-address": "test1",
"group1-permission-others": "test2",
"group1-permission-packet-capture": "test3",
"group1-permission-policy": "test4",
"group1-permission-schedule": "test5",
"group1-permission-service": "test6",
"group2-permission-config": "none",
"group2-permission-data-access": "none",
"group2-permission-report-access": "none",
"group2-permission-threat-weight": "none",
"group3-permission-antivirus": "none",
"group3-permission-application-control": "none",
"group3-permission-casi": "none",
"group3-permission-data-loss-prevention": "none",
"group3-permission-dnsfilter": "none",
"group3-permission-icap": "none",
"group3-permission-ips": "none",
"group3-permission-spamfilter": "none",
"group3-permission-voip": "none",
"group3-permission-waf": "none",
"group3-permission-webfilter": "none"
}发布于 2017-06-29 23:42:32
在我看来,这些文档是很好的,但它有助于对map有一定的熟悉程度,对管道和过滤器也有一定的舒适度。总之,这里有一个面向地图的解决方案:
to_entries
| map( .key as $key
| .value
| to_entries
| map ( { ($key + "-" + .key): .value } ) | add ) | add这里还有另一个,它适用于任意深度嵌套的JSON对象和数组:
[paths(scalars) as $path | { ($path|join("-")): getpath($path) }] | add当然,这里有一个警告:如果由于使用"-“作为连接字符而导致路径发生冲突,一些数据可能会丢失。
https://stackoverflow.com/questions/44836049
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