如何在plpgsql中使用变量内部函数

Question

我正在将一个来自触发器的值存储到函数中的一个变量中，当我使用function.Below中的变量是我的函数和触发器时，我得到了一个错误

CREATE OR REPLACE FUNCTION 
edm.automated_builder_update_trigger_manual()
RETURNS trigger AS
$BODY$
DECLARE
    e record;
    weekly_permit_table text := TG_ARGV[0];
BEGIN


Update  edm.weekly_permit_table as a
set applicant = applicant||' '||'-'||' '||new.builder where 
old.permit_number = split_part(a.permit_details, ' ',1);


RETURN NULL;
END;

还有我的扳机

CREATE TRIGGER builder_update_trigger_manual
 AFTER UPDATE
 ON edm.permit_table_manual_05_2017
 FOR EACH ROW
 WHEN (((old.builder)::text IS DISTINCT FROM (new.builder)::text))
 EXECUTE PROCEDURE 
edm.automated_builder_update_trigger_manual('weekly_permit_report_05_2017');

当我更新'edm.permit_table_manual_05_2017‘表中的构建器值时，正在获取错误’错误:关系edm.weekly_permit_table不存在‘’

我知道这可能很傻。但我不知道我哪里错了。

Answer 1

CREATE OR REPLACE FUNCTION edm.automated_builder_update_trigger_manual()
RETURNS trigger AS
$BODY$
DECLARE
  e record;
  weekly_permit_table text := TG_ARGV[0];
BEGIN
  EXECUTE 
    format(
      $q$
        UPDATE edm.%I AS a SET
          applicant = concat(applicant,' - '||$1)
        WHERE 
          $2 = split_part(a.permit_details, ' ',1)$q$,
      weekly_permit_table)
    USING NEW.builder, OLD.permit_number;
  RETURN NULL;
END $BODY$;

EXECUTE