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块async_generator
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Stack Overflow用户
提问于 2017-06-19 09:13:48
回答 1查看 2.3K关注 0票数 8

我可以让迭代器的块执行如下操作:

代码语言:javascript
复制
def get_chunks_it(l, n):
    """ Chunks an iterator `l` in size `n`
    Args:
        l (Iterator[Any]): an iterator
        n (int): size of
    Returns:
        Generator[Any]
    """
    iterator = iter(l)
    for first in iterator:
        yield itertools.chain([first], itertools.islice(iterator, n - 1))

现在假设我有一个异步生成器(python3.6):

代码语言:javascript
复制
async def generator():
    for i in range(0, 10):
        yield i
        await asyncio.sleep(1)

如何获得生成的async_generator的块(比方说大小为3的块将产生0、1、2、3、4、5、6、7、8、9),以便我可以编写:

代码语言:javascript
复制
async for chunk in get_chunk_it_async(generator(), 3):
    print(chunk)
EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2017-06-19 09:33:29

这在Python3.6中的函数中稍微复杂一些(一旦正确地从__aiter__返回一个awaitable,它将被添加到3.7中)。目前还没有itertools对象的异步版本。

定义你自己:

代码语言:javascript
复制
try:
    aiter
except NameError:
    # not yet a built-in, define our own shim for now
    from inspect import iscoroutinefunction as _isasync
    def aiter(ob, _isasync=_isasync):
        obtype = type(ob)  # magic methods are looked up on the type
        if not hasattr(obtype, '__aiter__'):
            raise TypeError(f'{obtype.__name__!r} object is not async iterable')
        async_iter = obtype.__aiter__(ob)
        if _isasync(async_iter):
            # PEP 492 allowed for __aiter__ to be a coroutine, but 525 reverses this again
            raise TypeError(f'{obtype.__name__!r} object is not async iterable')
        return async_iter
    del _isasync

接下来,您需要定义异步islicechain对象:

代码语言:javascript
复制
class achain():
    """Chain over multiple async iterators"""
    def __init__(self, *async_iterables):
        self._source = iter(async_iterables)
        self._active = None
    def __aiter__(self):
        return self
    async def __anext__(self):
        if self._source is None:
            # we are all done, nothing more to produce
            raise StopAsyncIteration
        if self._active is None:
            # get next async iterable to loop over
            ait = next(self._source, None)
            if ait is None:
                # we are all done, nothing more to produce
                self._source = None
                raise StopAsyncIteration
            self._active = aiter(ait)
        try:
            return await type(ait).__anext__(ait)
        except StopAsyncIteration:
            # exhausted, recurse
            self._active = None
            return await self.__anext__()

class aslice():
    """Slice an async iterator"""
    def __init__(self, ait, start, stop=None, step=1):
        if stop is None:
            start, stop = 0, start
        self._ait = ait
        self._next, self._stop, self._step = start, stop, step
        self._cnt = 0
    def __aiter__(self):
        return self
    async def __anext__(self):
        ait, stop = self._ait, self._stop
        if ait is None:
            raise StopAsyncIteration
        anext = type(ait).__anext__
        while self._cnt < self._next:
            try:
                await anext(ait)
            except StopAsyncIteration:
                self._ait = None
                raise
            self._cnt += 1
        if stop is not None and self._cnt >= stop:
            self._ait = None
            raise StopAsyncIteration
        try:
            item = await anext(ait)
        except StopAsyncIteration:
            self._ait = None
            raise
        self._cnt += 1
        self._next += self._step
        return item

在这些设置就绪后,只需将async添加到正确的位置:

代码语言:javascript
复制
async def get_chunks_it(l, n):
    """ Chunks an async iterator `l` in size `n`
    Args:
        l (Iterator[Any]): an iterator
        n (int): size of
    Returns:
        Generator[Any]
    """
    iterator = aiter(l)
    async for first in iterator:
        async def afirst():
            yield first
        yield achain(afirst, aslice(iterator, n - 1))
票数 5
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/44626518

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