给定2个来源实体:
class SourceA
{
public string Info1 { get; set; }
public string Info2 { get; set; }
}
class SourceB
{
public A A { get; set; }
public string OptionalExtraInfo { get; set; }
}还有一个目的地:
class Dest
{
public string ModifiedInfo1 { get; set; }
public string ModifiedInfo2 { get; set; }
public string ModifiedOptionalExtraInfo { get; set; }
}我想让下面的代码与EF6一起工作:
var destsFromA = dbContext.SourcesA.ProjectTo<Dest>().ToArray();
var destsFromB = dbContext.SourcesB.ProjectTo<Dest>().ToArray();因此,我定义了Automapper.net映射:
有关于如何将Info1投影到ModifiedInfo1中的自定义规则,以及Info2=>ModifiedInfo2:
CreateMap<SourceA, Dest>()
.ForMember(x => ModifiedInfo1, opt => opt.MapFrom(src => src.Info1 + " something else-1")
.ForMember(x => ModifiedInfo2, opt => opt.MapFrom(src => src.Info1 + " something else-2")
.ForMember(x => ModifiedOptionalExtraInfo, opt => opt.Ignore());
CreateMap<SourceB, Dest>()
.ForMember(x => ModifiedInfo1, opt => opt.MapFrom(src => src.A.Info1 + " something else-1")
.ForMember(x => ModifiedInfo2, opt => opt.MapFrom(src => src.A.Info2 + " something else-2")
.ForMember(x => ModifiedOptionalExtraInfo, opt => opt.MapFrom(src => src.OptionalExtraInfo + " something else-3"));如何在第二次映射中重用ModifiedInfo1、ModifiedInfo2的映射规则,因为它们与第一种情况相同?
UPDATE --在我的特定情况下--我了解了如何以自然的方式重用SourceA => Dest映射。
首先,我添加了反向引用(导航属性) SourceA.B,因为这些实体实际上处于一对零或一的关系中,EF必须知道这一点。
然后,我在我的应用程序代码中更改了聚合根,它变成:
var destsFromA = dbContext.SourcesA.ProjectTo<Dest>().ToArray();
var destsFromB = dbContext.SourcesB.Select(x => x.A).ProjectTo<Dest>().ToArray();所以我只需要处理唯一的SourceA => Dest映射
最后,我更改了映射本身:
CreateMap<SourceA, Dest>()
.ForMember(x => ModifiedInfo1, opt => opt.MapFrom(src => src.Info1 + " something else-1")
.ForMember(x => ModifiedInfo2, opt => opt.MapFrom(src => src.Info1 + " something else-2")
.ForMember(x => ModifiedOptionalExtraInfo, opt => opt.MapFrom(src => src.B ? src.B.OptionalExtraInfo + " something else-3" : null);由于这是一个问题的解决方案,而不是原来问题的答案,我接受了Ilya 的答案,认为他的答案是正确的。
发布于 2017-05-20 16:06:06
带有表达式的参数化映射:
opt.MapFrom(expression)
.ForMember(x => x.Foo, expression)使用ReSharper提取这些表达式变量很容易,因此可以如下所示:
Expression<Func<SourceA, string>> expression = src => src.Info1 + " something else-1";
var func = expression.Compile();
cfg.CreateMap<SourceA, Dest>()
.ForMember(x => x.ModifiedInfo1,
opt => opt.MapFrom(expression));
cfg.CreateMap<SourceB, Dest>()
.ForMember(x => x.ModifiedInfo1,
opt => opt.MapFrom(src => func(src.A)));更新:在LINQ转换的情况下,解决方案变得更加复杂。expression.Compile()不能工作,应该创建一个新的表达式:
Expression<Func<SourceA, string>> expression = src => src.Info1 + "foo";
//it should contain `src => src.A.Info1 + "foo"`
var newExpression = ConvertExpression(expression);基于ExpressionVisitor的基本实现
private static Expression<Func<SourceB, string>>
ConvertExpression(Expression<Func<SourceA, string>> expression)
{
var newParam = Expression.Parameter(typeof(SourceB), "src");
var newExpression = Expression.Lambda<Func<SourceB, string>>(
new ReplaceVisitor().Modify(expression.Body, newParam), newParam);
return newExpression;
}
class ReplaceVisitor : ExpressionVisitor
{
private ParameterExpression parameter;
public Expression Modify(Expression expression, ParameterExpression parameter)
{
this.parameter = parameter;
return Visit(expression);
}
protected override Expression VisitLambda<T>(Expression<T> node)
{
return Expression.Lambda<Func<SourceB, bool>>(
Visit(node.Body),
Expression.Parameter(typeof(SourceB)));
}
protected override Expression VisitParameter(ParameterExpression node)
{
if (node.Type == typeof(SourceA))
{
return Expression.Property(parameter, nameof(SourceB.A));
}
throw new InvalidOperationException();
}
} 发布于 2017-05-21 07:20:05
一个快速而简单的解决方案是使用中间类。
首先是所使用的类,然后在投递中使用
public class SourceA
{
public string A { get; set; }
}
public class SourceB
{
public string B { get; set; }
}
public class Dest
{
public string ValueFromSourceA { get; set; }
public string ValueFromSourceB { get; set; }
}这里说的是中间阶层:
public class Intermediate
{
public SourceA SourceA { get; set; } = new SourceA();
public SourceB SourceB { get; set; } = new SourceB();
}现在让我们开始用Automapper把零件粘在一起。
定义配置文件类
public class DestinationProfile : Profile
{
public DestinationProfile()
{
this.CreateMap<Intermediate, Dest>()
.ForMember(destination => destination.ValueFromSourceA,
opt => opt.MapFrom(src => src.SourceA.A))
.ForMember(destination => destination.ValueFromSourceB,
opt => opt.MapFrom(src => src.SourceB.B));
}
}
public class IntermediateProfile : Profile
{
public IntermediateProfile()
{
this.CreateMap<Intermediate, Dest>()
.ForMember(destination => destination.ValueFromSourceA, map => map.MapFrom(src => src.SourceA.A))
.ForMember(destination => destination.ValueFromSourceB, map => map.MapFrom(src => src.SourceB.B));
// ----- TODO: Create mapping for source classes.
}
}这是我们在上面标记的地图的重担。您可以使用Automapper的IValueResolver接口来定义值映射。所以在我们的例子中,解析器看起来像
public class SourceAResolver : IValueResolver<SourceA, Intermediate, SourceA>
{
public SourceA Resolve(SourceA source, Intermediate destination, SourceA destMember, ResolutionContext context)
{
return source;
}
}
public class SourceBResolver : IValueResolver<SourceB, Intermediate, SourceB>
{
public SourceB Resolve(SourceB source, Intermediate destination, SourceB destMember, ResolutionContext context)
{
return source;
}
}现在,我们可以替换todo语句。
this.CreateMap<SourceA, Intermediate>()
.ForMember(destination => destination.SourceA, map => map.ResolveUsing<SourceAResolver>());
this.CreateMap<SourceB, Intermediate>()
.ForMember(destination => destination.SourceB, map => map.ResolveUsing<SourceBResolver>());最后,我们将配置文件类注册到Automapper
public static class AutomapperProfile
{
public static void Configure()
{
Mapper.Initialize(cfg =>
{
cfg.AddProfile<DestinationProfile>();
cfg.AddProfile<IntermediateProfile>();
});
}
}用下面的代码片段启动控制台有助于测试我们的内容
AutomapperProfile.Configure();
var a = new SourceA {A = "Value A"};
var b = new SourceB() {B = "Value B"};
var intermediate = new Intermediate() {SourceA = a, SourceB = b};
var destination = AutoMapper.Mapper.Map<Dest>(intermediate);
Console.WriteLine(destination.ValueFromSourceA);
Console.Read();完成了!
注意:所提供的代码片段只是为了演示“中间”类的用法/含义--还没有实现返回到源类的方式。
(玩得开心:)
https://stackoverflow.com/questions/44086234
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