目前,我有这样的代码,它可以得到一个foodList:
var myDictionary = new System.Collections.Generic.Dictionary<string, object>();
myDictionary .Add("RefId",1);
myDictionary.Add("Type", "fruit");
var foodList = this.factoryService.GetMyService()
.GetByCriteria(sortOrder, NHibernate.Criterion.Restrictions.AllEq(myDictionary));我想使用MultiValueDictionary来收集多个类型。
var multiValueDictionary = new System.Collections.Generic.MultiValueDictionary<string, object>();
multiValueDictionary.Add("RefId",1);
multiValueDictionary.Add("Type", "fruit");
multiValueDictionary.Add("Type", "vegetable");
multiValueDictionary.Add("Type", "fungus");
var foodList = this.factoryService.GetMyService()
.GetByCriteria(sortOrder, NHibernate.Criterion.Restrictions.AllEq(multiValueDictionary));最后一行没有编译,因为MultiValueDictionary没有实现IDictionary,因此出现了以下错误:
错误'System.Collections.Generic.MultiValueDictionary‘参数1:无法从CS1503转换为“System.Collections.IDictionary”
我该怎么做?
发布于 2017-05-12 11:49:15
实现只是:
/对IDictionary /字典中的每个属性应用“等于”约束,从属性名称到值/ public静态AbstractCriterion AllEq(IDictionary propertyNameValues) { conj =conj();foreach (propertyNameValues中的DictionaryEntry项){ conj.Add(Eq(item.Key.ToString(),item.Value));}返回conj;}
因此,对于多值情况,可以停止将其放在字典中,然后手动添加:
var myDictionary = new Dictionary<string, object>();
myDictionary.Add("RefId", 1);
var filter = (Conjunction)Restrictions.AllEq(myDictionary);
filter.Add(Restrictions.In("Type", new [] {"fruit", "vegetable", "fungus"});
var foodList = this.factoryService.GetMyService()
.GetByCriteria(sortOrder, filter);当然,如果现在只有RefId可以放在字典中,那么最好简化它:
var filter = Restrictions.Conjunction();
filter.Add(Restrictions.Eq("RefId", 1));
filter.Add(Restrictions.In("Type", new [] {"fruit", "vegetable", "fungus"}));
var foodList = this.factoryService.GetMyService()
.GetByCriteria(sortOrder, filter);现在,如果您想要一个处理多值的AllIn,那么对它进行编码:
public static AbstractCriterion AllIn<TValue>(
MultiValueDictionary<string, TValue> propertyNameValues)
{
var conj = Restrictions.Conjunction();
foreach (KeyValuePair<TKey, IReadOnlyCollection<TValue>> item in propertyNameValues)
{
if (item.Value.Count > 1)
{
conj.Add(Restrictions.In(item.Key, item.Value.ToArray()));
}
else
{
conj.Add(Restrictions.Eq(item.Key, item.Value.FirstOrDefault()));
}
}
return conj;
}https://stackoverflow.com/questions/43924662
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