我不知道如何从角谷歌地图实例调用fitBounds()。我试图在uiGmapGoogleMapApi解析后调用它,但是我不知道在哪里/如何访问这个方法。从普通的js实现中,您可以调用map.fitBounds(界),但我不确定在角-google v2.2.1中等效的是什么,谢谢您的帮助。
编辑
我将控件属性添加到scope.map中,然后在getGMap()解析时调用uiGmapIsReady ()。
uiGmapGoogleMapApi.then(function(maps) {
scope.bounds = new maps.LatLngBounds();
scope.map = {
center: {
latitude: 47.60427,
longitude: -122.33825
},
zoom: 16,
polys: [],
bounds: {},
control: {} // add this property
};
traceVehicle(scope.tripDetails);
});
// add uiGmapIsReady and call getGMap()
uiGmapIsReady.promise(1).then(function(instances) {
instances.forEach(function(inst) {
var map = inst.map;
var uuid = map.uiGmap_id;
var mapInstanceNumber = inst.instance; // Starts at 1.
var gMap = scope.map.control.getGMap(); // assign getGMap();
gMap.fitBounds(scope.bounds);
});
});
function traceVehicle(selectedTrip) {
var rawPolys = [];
var polylineObj = {
id: 1,
path: [],
stroke: {
color: '#6060FB',
weight: 3
},
editable: false,
draggable: false,
geodesic: true,
visible: true
};
scope.polylines = [];
if(selectedTrip.locations.length > 0) {
angular.forEach(selectedTrip.locations, function(v, i) {
polylineObj.path.push({ latitude: v.lat, longitude: v.lon });
scope.bounds.extend({ lat: v.lat, lng: v.lon });
});
rawPolys.push(polylineObj);
scope.map = {
center: {
latitude: polylineObj.path[(Math.round(polylineObj.path.length/2) -1)].latitude,
longitude: polylineObj.path[(Math.round(polylineObj.path.length/2) -1)].longitude
},
zoom: 16,
polys: rawPolys
};
scope.map.fitBounds(scope.bounds); // how to call fitBounds()?发布于 2017-05-11 00:00:45
您将需要$scope.map成为谷歌地图对象。目前这只是个选择。
var mapOptions = {
zoom: 16,
polys: [],
bounds: {},
center: new google.maps.LatLng(47.60427, -122.33825),
mapTypeId: google.maps.MapTypeId.TERRAIN
};
$scope.map = new google.maps.Map(document.getElementById('map'), mapOptions);
$scope.map.fitBounds(YOUR_CODE_FOR_BOUNDS);https://stackoverflow.com/questions/43903869
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