由信件制成的信件

Question

我是python的新手(3.4版)。我想知道我怎么能做一个类似于这个的代码：

#block letters 
B1 = ("BBBB  ")
B2 = ("B   B ")
B3 = ("B   B ")
B4 = ("BBBB  ")
B5 = ("B   B ")
B6 = ("B   B ")
B7 = ("BBBB  ")
B = [B1, B2, B3, B4, B5, B6, B7]

E1 = ("EEEEE ")
E2 = ("E     ")
E3 = ("E     ")
E4 = ("EEEEE ")
E5 = ("E     ")
E6 = ("E     ")
E7 = ("EEEEE ")
E = [E1, E2, E3, E4, E5, E6, E7]

N1 = ("N    N")
N2 = ("NN   N")
N3 = ("N N  N")
N4 = ("N N  N")
N5 = ("N  N N")
N6 = ("N   NN")
N7 = ("N    N")
N = [N1, N2, N3, N4, N5, N6, N7]
for i in range(7):
    print(B[i], E[i], N[i])

我当前代码的输出如下所示：

BBBB   EEEEE  N    N
B   B  E      NN   N
B   B  E      N N  N
BBBB   EEEEE  N N  N
B   B  E      N  N N
B   B  E      N   NN
BBBB   EEEEE  N    N

但我想知道如何做一个可以接受用户的输入，并打印在上面的风格。我已经尝试了几个小时了，但找不出一个解决方案，看看其他人怎么做就太好了。我认为当屏幕上不适合其他字母时，这会变得更加困难，所以我只想打印10个字母。谢谢

Answer 1

首先你必须像以前一样手工制作字母表

N1 = ("N    N")
N2 = ("NN   N")
N3 = ("N N  N")
N4 = ("N N  N")
N5 = ("N  N N")
N6 = ("N   NN")
N7 = ("N    N")
N = [N1, N2, N3, N4, N5, N6, N7]

每封信都要这样做。阿-兹

# Now to let user input print your alphabet we will use a dictionary
# The the key is the letter and value is the printable  array
d = {'a':A,'b':B, ... , 'z':Z }

# Let's ask for user input:
line = input('What do you want to print> ')

# Now lets print what the user said in our alphabet
# iterate through the input and print it

sentence = map(d.get,line)
for letter in zip(*sentence):
    print(*letter)

Answer 2

在不变得非常复杂的情况下，您需要硬核(即静态定义)每个字母为字符串列表，类似于您如何使用B、E和N。

然后构建一个字典，将每个字母映射到相应的列表：

>>> letters = {
...     'b': ["BBBB  ", "B   B ", "B   B ", "BBBB  ", "B   B ", "B   B ", "BBBB  "],
...     'e': ["EEEEE ", "E     ", "E     ", "EEEEE ", "E     ", "E     ", "EEEEE "],
...     'n': ["N    N", "NN   N", "N N  N", "N N  N", "N  N N", "N   NN", "N    N"]
... }

此示例只包含字母b、e和n的定义，您需要自己添加所有其他字母的定义。确保所有列表都有相同的长度。完成之后，您可以使用本词典显示从用户输入中获得的任何字母序列。演示：

>>> name = raw_input('enter your name: ')
enter your name: Ben
>>>
>>> for row in zip(*[letters[x.lower()] for x in name]):
...     print ''.join(row)
... 
BBBB  EEEEE N    N
B   B E     NN   N
B   B E     N N  N
BBBB  EEEEE N N  N
B   B E     N  N N
B   B E     N   NN
BBBB  EEEEE N    N

Answer 3

我找到了一个不那么复杂的答案。我不知道如何使用zip或map，但是如果没有them.And，我可以理解代码所做的事情。

A =["   A    ", #CREATING LIST OF LETTERS
    "  A A   ",
    " A   A  ",
    "AAAAAAA ",
    "A     A ",
    "A     A ",
    "A     A "]

以这种方式创建字母表：

#PUTTING LETTERS IN LIST
Alphabet = {"A":A,"B": B, "C": C, "D":D, "E":E ,"F":F, "N": N} 
#ASKER USER FOR INPUT
text = input('Enter text(Only takes A, B, C, D, E, F, N)? ')
#INPUT IN UPPERCASE
text = text.upper()
for i in range(7):
    for letter in text:
        temp = Alphabet[letter]
        print(temp[i],end="")
    print('')