将查询过滤器应用于JavaScript对象数组

Question

const sample_table1_data = [
    { title: 'aa-1', customers: ['a', 'b']},
    { title: 'aa-2', customers: ['a', 'c']},
    { title: 'bb-1', customers: ['d', 'e']},
    { title: 'cc-1', customers: ['b', 'e', 'f']},
    { title: 'dd-1', customers: ['f', 'g']},
    { title: 'dd-2', customers: ['g']},

]

我正在尝试过滤看起来像上面的对象数组。假设我同时查询title和customer，前者是一个字符串，后者是一个字符串数组。

我创建了一个名为filterData的函数，该函数采用如下所示的对象

let filter_info = {
    title: ['aa, cc'], customer: ['b']
}

我希望该函数过滤掉在title中具有aa和在customers中具有b的对象，期望输出为

output = [
    { title: 'aa-1', customers: ['a', 'b']},
    { title: 'cc-1', customers: ['b', 'e', 'f']},
]

因为这是满足查询的两个对象(title包括aa和cc，customers包括'b')

我试过了

filterData = (filters) => {
    let title_filter = filters.title
    let customer_filter = filters.customer
    const myItems = this.state.table1_data

    const keywordsToFindLower = title_filter.map(s => s.toLowerCase());
    const customerKeywords = customer_filter.map(s => s.toLowerCase())

    // filters the profile data based on the input query (selected option)
    const newArray = myItems.filter(item =>
        keywordsToFindLower.some(
            title_filter => (item.title.toLowerCase()).includes(title_filter)
        ) 
        &&
        customerKeywords.some(
            customer_filter => (item.customers.toLowerCase()).includes(customer_filter)
        ) 
    )
}

但是，这给了我一个错误，因为customers是一个数组，而不是一个字符串。

如果我想完成这个任务，正确的用法是什么？

Answer 1

你就快到了。您可以在filter方法中的customers数组上使用Array.some()，如下所示：

item.customers.some(value => value.toLowerCase().includes(customer_filter))

那么您的filter方法将如下所示：

const newArray = myItems.filter(item =>
        keywordsToFindLower.some(
            title_filter => (item.title.toLowerCase()).includes(title_filter)
        ) 
        &&
        customerKeywords.some(
            customer_filter =>
              (item.customers.some(
                 value => value.toLowerCase().includes(customer_filter))
              )
        ) 
    )